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From: tmnhuda09 on 4 Jun 2010 09:50
The real and imaginary have the same PDF(Gaussain PDF)after IFFT of complex
signal. But in my matlab code it looks different. why? can anybody explain
it please? here is my code

N=10;
ml=2;
for p=0:1000-1
x=randint(N*ml,1)*2-1;
ich = x((1:N),1);
qch = x((N+1:ml*N),1);
x1=ich+qch*i;
y=ifft(x1,10);
yr=real(y);
yi=imag(y);
env=sqrt(yr.^2+yi.^2);
for i=1:10
real_p(p*10+i)=yr(i);
ima_p(p*10+i)=yi(i);
st(p*10+i)=env(i);
end
end




Best regards
T.M. Nazmul Huda



From: Greg Heath on 4 Jun 2010 16:51
On Jun 4, 9:50 am, "tmnhuda09" <tmnhuda09(a)n_o_s_p_a_m.gmail.com>
wrote:
> The real and imaginary have the same PDF(Gaussain PDF)after IFFT of complex
> signal. But in my matlab code it looks different. why? can anybody explain
> it please? here is my code
>
>  N=10;
> ml=2;
> for p=0:1000-1
> x=randint(N*ml,1)*2-1;
>  ich = x((1:N),1);
>  qch = x((N+1:ml*N),1);
>  x1=ich+qch*i;
> y=ifft(x1,10);
> yr=real(y);
> yi=imag(y);
> env=sqrt(yr.^2+yi.^2);
> for i=1:10
>     real_p(p*10+i)=yr(i);
>     ima_p(p*10+i)=yi(i);
>     st(p*10+i)=env(i);
> end
> end
>
> Best regards
> T.M. Nazmul Huda

I don't have randint. However, I interpret the documentation
to mean that randint(m,n) is the same as round(rand(m,n)).
Both cases are distributed uniformly, not normally.

Hope this helps.

Greg
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