Can I pass the output of some command to two or more commands without using a temporay file?
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From: PRC on 17 Apr 2008 23:45 Hi All, Is there a easy way in bash to pass the output of running CMD1 to 2 or more commands CMD2, CMD3, ... etc, without saving the output of CMD1 to a temporary file? It is no good saving the output in a varible since bash converts the tailing '\r's to spaces. The tranditional way looks like: CMD1>tmpfile CMD2<tmpfile CMD3<tmpfile .... CMDn<tmpfile rm -f tmpfile Best Regards, PRC Apr 18, 2008
From: Florian Kaufmann on 18 Apr 2008 01:58 In bash yes. It's a non POSIX solution. cmd1 | tee >(cmd2) >(cmd2) >(cmd...) | cmdN Flo
From: Florian Kaufmann on 18 Apr 2008 02:04 In bash yes. It's a non POSIX solution. cmd1 | tee >(cmd1) >(cmd2) >(cmd...) | cmdN Man tee says: tee [OPTION]... [FILE]... Copy standard input to each FILE, and also to standard output. >(...) is the syntax for process substitution. Simplified, it can stay where ever a command expects a file name as argument to which it will write. <(...) likewise for files the process will read from. http://tldp.org/LDP/abs/html/process-sub.html Flo
From: Dave B on 18 Apr 2008 04:20
On Friday 18 April 2008 05:45, PRC wrote: > It is no good saving the output in a varible since bash converts the > tailing '\r's to spaces. No it doesn't, unless you let it do that. $ ls file1 file2 file3 file4 $ myvar=`find -type f` $ echo $myvar # lose format ../file1 ./file2 ./file3 ./file4 $ echo "$myvar" # keep format ../file1 ../file2 ../file3 ../file4 -- D. |