From: Dirk Bell on
On May 6, 9:44 am, Jerry Avins <j...(a)ieee.org> wrote:
> On 5/6/2010 9:26 AM, jumpfunky wrote:
>
>    ...
>
> > For n = 1 the frequency of sine is 0.1 Hz. For n = 512 the frequency is
> > 51,2Hz. Since the frequency of the chirp-Signal grows linear, the sine
> > contains only frequencys between 0.1Hz and 51,2Hz.
>
> That's an understandable error that has been made before. It is
> tantamount to the claim that a frequency modulated signal fits into a
> channel as wide as its peak deviation. "Taint so. It has to be wider.
>
>    ...
>
> Jerry
> --
> "I view the progress of science as ... the slow erosion of the tendency
>   to dichotomize." --Barbara Smuts, U. Mich.
> ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

I think the problem is more than that. The OP needs to take the
derivative of the phase to figure out what the instantaneous frequency
should be. I think that will answer his question. Missing a factor of
2 in his expectations.

Dirk