Date function problem
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From: bruce on 28 Apr 2010 20:17 On Apr 28, 7:21 pm, RobG <rg...(a)iinet.net.au> wrote: > On Apr 28, 1:11 pm, bruce <bruc...(a)bellsouth.net> wrote: > > > The input for this this code is YearT=2010, MonthIndex=3, DayT = 27, > > Start_HourT = 22, Start_MinutesT=15, > > End_HourT = 20, End_MinutesT = 15 > > By convention, variable names starting with a capital letter signify > constructors or, where all characters are upper case, constants. Code > is much easier to read if neatly indented and, when posted to a news > group, manually wrapped at about 70 characters. > > > > > var InputStart = new Date(); > > var InputEnd = new Date(); > > There's no point initialising variables with a value that you > immediately overwrite. > > > InputStart = Date(YearT, MonthIndex, DayT, Start_HourT,Start_MinutesT, > > 0,0); > > InputEnd = Date(YearT, MonthIndex, DayT, End_HourT, End_MinutesT,0,0); > > Here you overwrite the intial values assigned to these variables, > trivialising in the initial assignment. In ECMAScript, variables do > not have a type (their values do), you can assign any type to any > variable so there is no need to initialise them if you don't want to. > > > alert(Start_HourT + ":" + End_HourT); // output is 22:20 Correct > > output > > > alert("==: " + (InputStart == InputEnd)); // Output is true?? Output > > Not Correct > > Consider (wrapped for posting): > > var yearT=2010, > monthIndex=3, > dayT = 27, > start_HourT = 22, > start_MinutesT=15, > end_HourT = 20, > end_MinutesT = 15, > inputStart = new Date(yearT, monthIndex, dayT, > start_HourT, start_MinutesT, 0, 0), > inputEnd = Date(yearT, monthIndex, dayT, end_HourT, > end_MinutesT, 0, 0); > > alert(inputStart == inputEnd); // false > > -- > Rob I "Solved" my compare problem by adding ".toString()" to both InputStart and InputEnd; Thanks for the help.. Bruce |