Extract a filename from a URL
in [Shell]
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From: StephaneLeFou on 24 Jun 2008 09:40 Hi, From a shell script, I'd like to extract the filenames (file001...file004) provided by a flat file that looks like: /disk2/incoming/file001;ABC;0000000010 /disk2/incoming/file002;ABC;0000000033 /disk2/incoming/file003;ABC;0000000002 /disk2/incoming/file004;ABC;0000000099 How do I extract those filenames and put them inside a varible for example (in a loop)? Thanks for your help.
From: Peter van Hooft on 24 Jun 2008 09:46 On 2008-06-24, StephaneLeFou <stephanelefou(a)gmail.com> wrote: > Hi, > > From a shell script, I'd like to extract the filenames > (file001...file004) provided by a flat file that looks like: > > /disk2/incoming/file001;ABC;0000000010 > /disk2/incoming/file002;ABC;0000000033 > /disk2/incoming/file003;ABC;0000000002 > /disk2/incoming/file004;ABC;0000000099 > > How do I extract those filenames and put them inside a varible for > example (in a loop)? > > Thanks for your help. It depends on what type of shell you use. In bash, zsh and ksh the following should work for i in "/disk2/incoming/file001;ABC;0000000010" \ "/disk2/incoming/file002;ABC;0000000033" \ "/disk2/incoming/file003;ABC;0000000002" \ "/disk2/incoming/file004;ABC;0000000099" do file=${i##*/} file=${file%%;*} echo $file done peter
From: Dave B on 24 Jun 2008 10:05 StephaneLeFou wrote: > Hi, > > From a shell script, I'd like to extract the filenames > (file001...file004) provided by a flat file that looks like: > > /disk2/incoming/file001;ABC;0000000010 > /disk2/incoming/file002;ABC;0000000033 > /disk2/incoming/file003;ABC;0000000002 > /disk2/incoming/file004;ABC;0000000099 > > How do I extract those filenames and put them inside a varible for > example (in a loop)? Many ways: awk -F';' '{print $1}' yourfile cut -d';' -f 1 yourfile sed 's/\([^;]*\).*/\1/' yourfile grep -o '[^;]*' yourfile all of these can be piped to a loop. -- echo 0|sed 's909=oO#3u)o19;s0#0ooo)].O0;s()(0bu}=(;s#}#.1m"?0^2{#; s)")9v2@3%"9$);so%op]t(p$e#!o;sz(z^+.z;su+ur!z"au;sxzxd?_{h)cx;:b; s/\(\(.\).\)\(\(..\)*\)\(\(.\).\)\(\(..\)*#.*\6.*\2.*\)/\5\3\1\7/; tb'|awk '{while((i+=2)<=length($1)-18)a=a substr($1,i,1);print a}'
From: Juha Laiho on 24 Jun 2008 10:12 StephaneLeFou <stephanelefou(a)gmail.com> said: >From a shell script, I'd like to extract the filenames >(file001...file004) provided by a flat file that looks like: > >/disk2/incoming/file001;ABC;0000000010 >/disk2/incoming/file002;ABC;0000000033 >/disk2/incoming/file003;ABC;0000000002 >/disk2/incoming/file004;ABC;0000000099 > >How do I extract those filenames and put them inside a varible for >example (in a loop)? sed 's:.*/::; s:;.*::' flatfile | while read file; do echo $file done .... and explained in parts (recommended that you also experiment with these pieces yourself): sed 's:.*/::; s:;.*::' flatfile will process 'flatfile' by reading it a line a the time, removing from start the longest possible part of the line that ends with character / (the s:.*/:: part; it is a substitution operation, where the replacement is an empty string), and then removing the longest possible part of the line that starts with a semicolon (the s:;.*:: part, similar substitution to the above). So, if you run the above part by itself, it will print out just the file names. Then to the "processing": while read file; do echo $file done will simply read its input one line at a time, and assign the contents of that line to variable called "file" (just a name I picked, could be more or less anything). The 'echo $file' will then just output the variable - but here is where you could place your own processing; whatever you would like to do with the file names. -- Wolf a.k.a. Juha Laiho Espoo, Finland (GC 3.0) GIT d- s+: a C++ ULSH++++$ P++@ L+++ E- W+$@ N++ !K w !O !M V PS(+) PE Y+ PGP(+) t- 5 !X R !tv b+ !DI D G e+ h---- r+++ y++++ "...cancel my subscription to the resurrection!" (Jim Morrison)
From: Dave B on 24 Jun 2008 10:18
Dave B wrote: > StephaneLeFou wrote: > >> Hi, >> >> From a shell script, I'd like to extract the filenames >> (file001...file004) provided by a flat file that looks like: >> >> /disk2/incoming/file001;ABC;0000000010 >> /disk2/incoming/file002;ABC;0000000033 >> /disk2/incoming/file003;ABC;0000000002 >> /disk2/incoming/file004;ABC;0000000099 >> >> How do I extract those filenames and put them inside a varible for >> example (in a loop)? > > Many ways: > > awk -F';' '{print $1}' yourfile > cut -d';' -f 1 yourfile > sed 's/\([^;]*\).*/\1/' yourfile > grep -o '[^;]*' yourfile > > all of these can be piped to a loop. Sorry, I misread your question. Try these: awk -F'[/;]' '{print $4}' yourfile sed 's_.*/\([^/;]*\);.*_\1_' yourfile -- echo 0|sed 's909=oO#3u)o19;s0#0ooo)].O0;s()(0bu}=(;s#}#.1m"?0^2{#; s)")9v2@3%"9$);so%op]t(p$e#!o;sz(z^+.z;su+ur!z"au;sxzxd?_{h)cx;:b; s/\(\(.\).\)\(\(..\)*\)\(\(.\).\)\(\(..\)*#.*\6.*\2.*\)/\5\3\1\7/; tb'|awk '{while((i+=2)<=length($1)-18)a=a substr($1,i,1);print a}' |