HOPE RESEARCH -- THE SQUARE ROOT OF 1( UNDERROOT), RECIPROCAL EQUALIZATION OF THE SQRT OF 2 AND 0.5-- CLARIFICATION OF TRIUNE DIFFERENTIAL OF 1
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From: Inverse 19 mathematics on 6 Aug 2010 14:43 WE Understand all this is new and different and "provokes envy/sour grapes amongst some stupid and inadequate fermatist" Fermatists" etc, but that is the way it is , Mathematics is what it is, None of you Own it. 0.41421356237 + 0.58578643763 = 1 exact 1^2=1 (code .999 0.999 0.999 1) 0.5 -0.41421356237 =- 0.08578643763 eaxct 0.5 -0.58578643763 = 0.08578643763 exact 0.4999 - 0.41421356237 = 0.08588643763 exact 0.4999-0.58578643763 = 0.08568643763 exact 0.41421356237/0.58578643763 = SQRT of " 0.5" 0.58578643763/0.41421356239 = SQRT of " 2" THUS the square root of 0.5 and sqrt of 2, have a reciprocal relationship to the sqrt of 1 and are reciprocally equal, i.e twice the value of sqrt of 0.5 , = 1/2 the value of sqrt of 2 THE only rational mathematical resolution is the following mathematics , which is also the proof of Inverse 19 1:3 and 1;6 Which very few fermatists will understand , certainly not the profane (f) fermatists. ).5 can ONLY be reciprocal to the sqrt of 1 with 2, if the value of square root 1 is "triune" with the following mathemmatical values +1x (0.333 , 0.333, 0.333 )=.999 with a fourth value 1-(.333+.333+. 333) =.001 2*3=6--- 3 0.5*4=2---1 (0.333) >>>> -1(0.999) 2* 3=4 " We call this 3 and equalizationof mathematics"*** 0.5*2=1 (0.25) >>> +1 |