From: Hari LKML on
After reading some of the books and the codes here is my understanding
about the tasklet_action function

the function statrs some thing like this

1. If the tasklet is not running in another processor set the Bit
TASKLET_STATE_RUN; ��� <<if (tasklet_trylock(t))>>
2. clear the TASKLET_STATE_SCHED bit;������ <<if (!test_and_clear_bit(TASKLET_
STATE_SCHED, &t->state))>>
3. start the tasklet � � <<(��� t->func(t->data))>>


Now when the tasklets function is running and the same interrupt is
raised again but now handled by a different processor (in a SMP
system) the tasklet is now scheduled in a different processor (because
the TASKLET_STATE_SCHED is already cleared in step 2)
and there are every chance of the same type of� taklet running
concurently in different processors thus braking the promise that same
types of tasklets do not ever run simultaniously.

I think i have misunderstood one or the other concept so please
correct me and help me in understanding the Linux Kernel code more
clearly.


Please personally CC me all answers/comments posted to the list, to my
mail id hari.lkml(a)gmail.com.

Hari
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From: Jiri Slaby on
On 06/19/2010 08:36 PM, Hari LKML wrote:
> After reading some of the books and the codes here is my understanding
> about the tasklet_action function
>
> the function statrs some thing like this
>
> 1. If the tasklet is not running in another processor set the Bit
> TASKLET_STATE_RUN; <<if (tasklet_trylock(t))>>
> 2. clear the TASKLET_STATE_SCHED bit; <<if (!test_and_clear_bit(TASKLET_
> STATE_SCHED, &t->state))>>
> 3. start the tasklet <<( t->func(t->data))>>
>
>
> Now when the tasklets function is running and the same interrupt is
> raised again but now handled by a different processor (in a SMP
> system) the tasklet is now scheduled in a different processor (because
> the TASKLET_STATE_SCHED is already cleared in step 2)
> and there are every chance of the same type of taklet running
> concurently in different processors thus braking the promise that same
> types of tasklets do not ever run simultaniously.
>
> I think i have misunderstood one or the other concept so please
> correct me and help me in understanding the Linux Kernel code more
> clearly.

But tasklet_trylock will return 0 when t->func is running on another
processor already because of step 1. Thus the tasklet gets to the end of
the tasklet list and is tried again later.

--
js
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