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From: Fortran_follower on 18 Feb 2010 10:28
1 Oct 2001 0 42 54 -41.646074 145.901599 463.240034
1 Oct 2001 0 42 55 -41.709808 145.902872 463.242092
1 Oct 2001 0 42 56 -41.773542 145.904157 463.244112
1 Oct 2001 0 42 57 -41.837276 145.905452 463.246094
1 Oct 2001 0 42 58 -41.901010 145.906758 463.248037
1 Oct 2001 0 42 59 -41.964742 145.908075 463.249943
1 Oct 2001 0 43 0 -42.028475 145.909403 463.251810
1 Oct 2001 0 43 1 -42.092143 145.910741 463.253637
1 Oct 2001 1 3 23 -59.581230 -46.330899 443.193713
1 Oct 2001 1 3 24 -59.517300 -46.323166 443.165155
1 Oct 2001 1 3 25 -59.453369 -46.315479 443.136587
1 Oct 2001 1 3 26 -59.389436 -46.307836 443.108010
1 Oct 2001 1 3 27 -59.325502 -46.300238 443.079424
1 Oct 2001 1 3 28 -59.261565 -46.292684 443.050827
1 Oct 2001 1 3 29 -59.197627 -46.285174 443.022221

Dear friends,

In the above shown data, column 4 represents, hour. I want to
calculate the hourly mean or 8,9 & 10th columns, from the above data
file.
What I know is, read 2 lines at a time and compare hour-value, whether
it reached next hour or not.
Can anyone please tell me is there any other simple way to do the
same.

I know as in Matlab, we load complete file into an array and can play
with the columns & rows as required. Is there anything similar in
fortran too..!!

Thanking you.

Praveen.
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