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From: CM on 16 May 2010 14:57
> > I need help with getting the useful information how do I get the place
> > if I don't now how long the string is?
>
>         And is it supposed to handle
>
>         for london give the weather to me
>         for the london weather give me
>
> ...
>
>         Do a search on "natural language processing"... You are at the level
> of algorithms, and algorithms are not limited to Python...

Yes, this is a major field of research. For basic purposes in Python,
maybe just try to trigger off the presence of the word "weather" and
the presence of a particular city's name. It will not work if the
user tries to trick it ("Don't give me the weather in London"), but,
like a search engine, it will more or less give what people want for
common queries. Like:

list_of_cities = ['london', 'moscow', 'new york', 'paris']
user_string = 'Give me the weather for London please.'
user_word_list = user_string.split() #if they put a comma after city,
this will be a problem
for word in user_word_list:
period_free_word = word.rstrip('.') #strips trailing period for
final word, in case there
lowered_word = period_free_word.lower() #makes it case
insensitive
if lowered_word in list_of_cities:
print 'The city is: ' + lowered_word
DoSomething(lowered_word) #go and get the weather data for
that city I guess

Che




From: CM on 16 May 2010 15:08
On May 16, 2:57 pm, CM <cmpyt...(a)gmail.com> wrote:
> > > I need help with getting the useful information how do I get the place
> > > if I don't now how long the string is?
>
> >         And is it supposed to handle
>
> >         for london give the weather to me
> >         for the london weather give me
>
> > ...
>
> >         Do a search on "natural language processing"... You are at the level
> > of algorithms, and algorithms are not limited to Python...
>
> Yes, this is a major field of research.  For basic purposes in Python,
> maybe just try to trigger off the presence of the word "weather" and
> the presence of a particular city's name.  It will not work if the
> user tries to trick it ("Don't give me the weather in London"), but,
> like a search engine, it will more or less give what people want for
> common queries.  Like:
>
> list_of_cities = ['london', 'moscow', 'new york', 'paris']
> user_string = 'Give me the weather for London please.'
> user_word_list = user_string.split()  #if they put a comma after city,
> this will be a problem
> for word in user_word_list:
>     period_free_word = word.rstrip('.') #strips trailing period for
> final word, in case there
>     lowered_word = period_free_word.lower()  #makes it case
> insensitive
>     if lowered_word in list_of_cities:
>          print 'The city is: ' + lowered_word
>          DoSomething(lowered_word)  #go and get the weather data for
> that city I guess
>
> Che

I forgot to split on two delimiters (a space and a comma). See here:
http://mail.python.org/pipermail/tutor/2008-August/063570.html

Anyway, you get the idea...
From: Gregory Ewing on 17 May 2010 03:26
Dennis Lee Bieber wrote:

> And is it supposed to handle
>
> for london give the weather to me
> for the london weather give me

Or

Where can I buy some new weather boarding for my
house in London?

:-)

--
Greg

>
> ...
>
> Do a search on "natural language processing"... You are at the level
> of algorithms, and algorithms are not limited to Python...
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