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From: Opal on 9 Feb 2010 15:07
But I need to rank a row of data

B2 to B.......

Your example looks like it will rank a column
not a row.... am I mistaken?

From: Jef Gorbach on 9 Feb 2010 17:53
On Feb 9, 3:07 pm, Opal <tmwel...(a)hotmail.com> wrote:
> But I need to rank a row of data
>
> B2 to B.......
>
> Your example looks like it will rank a column
> not a row.... am I mistaken?

Correct, data is typically arranged vertically in columns (ie B2:B#).
for example:

column A column B
Date Sales
1-01-2010 14
1-02-2010 5
1-03-2010 15
1-04-2010 22

On the other hand, if your data is arranged horizontally across a row
(ie: A6:G6 for instance) then give this a try:
for example

date






Sub MacroTryThis2()
'delete the "Ranked Values" worksheet if it already exists
Application.DisplayAlerts = False
On Error Resume Next
Worksheets("Ranked Values").Delete
Application.DisplayAlerts = True
On Error GoTo 0
'copy sheet1 to a new tab then name it Ranked Values
Sheets("Sheet1").Select
Sheets("Sheet1").Copy After:=Sheets(1)
ActiveSheet.Name = "Ranked Values"

'presuming Column(A) is your longest one, start at its bottom and look
upwards until we find the last row of your data
LastRow = Range("A65536").end(xlup).row

'sort ("rank") across the last row of data smallest to largest
(ascending)
Rows(LastRow).Sort Key1:=Range("A6"), Order1:=xlAscending,
Header:=xlGuess, _
OrderCustom:=1, MatchCase:=False, Orientation:=xlLeftToRight,
_
DataOption1:=xlSortNormal

'end with the cursor at cell B2
Range("B2").Select
End Sub



From: Opal on 10 Feb 2010 13:59
Hmmmm compile error:

"Function call on left-hand side of assignment must return Variant or
Object"

BTW, data has been arranged in this manner:


Weekof Part A Part B Part C
01/04-01/09 6.7 5.4 3.2
01/11-01/16 7.1 4.9 5.1
01/18-01-23 6.3 6.1 8.2

I need to rank the data week by week

If I switch it to the way you first suggested I will eventually run
out of columns
as the part numbers range from 11 to 28 depending on the production
line but
the weeks in a year or years will continue to grow.
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