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From: Zuhaina Zakaria on 8 Feb 2005 06:32
I'm sorry using this forum for this purpose but I really need to get
in touch with Bora. Below is my message for him.
_________________________________________________________

Hi,

Back in Aug last year you responded to my question posted in Matlab
central forum regarding least square problem. I pasted below for your
reference. I really appreciate if you can help me again..

------------------(your respond earlier)
One approach might be (when x+y+z = 1)

[C1 C2 C3; a*1 a*1 a*1] [x y z] = [L ; a*1]

And solve for (x,y,z) using \.
And the value of "a" would let you adjust the weight on the equality
constraint.

Bora
----------------------

I found that if I use a=1, I will get x+y+z=1. However, if I have now
only two constant as below:

[C1 C2; a*1 a*1] [x y] = [L; a*1]

and use a=1, I can't get x+y+z=1. I tried to use other values of a
but is more like a trial and error approach. Do you think I need some
kind of optimization here?

I really hope you can help me. Thank you in advance.


Best regards,

Zuhaina Zakaria
Power System Research Group
Dept of Electronic and Electrical Engineering
University of Strathclyde
Glasgow G1 1XW

Tel: 0141 5482638
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