From: Eric W. Biederman on
From: Eric W. Biederman <ebiederm(a)xmission.com>

Strictly speaking on x86 (where acpi is used) dev->irq must be
a dual i8259 irq input aka an isa irq. Therefore we should translate
that isa irq into a gsi before passing it to a function that
takes a gsi.

Signed-off-by: Eric W. Biederman <ebiederm(a)xmission.com>
---
drivers/acpi/pci_irq.c | 8 +++++---
1 files changed, 5 insertions(+), 3 deletions(-)

diff --git a/drivers/acpi/pci_irq.c b/drivers/acpi/pci_irq.c
index 843699e..703541d 100644
--- a/drivers/acpi/pci_irq.c
+++ b/drivers/acpi/pci_irq.c
@@ -400,11 +400,13 @@ int acpi_pci_irq_enable(struct pci_dev *dev)
* driver reported one, then use it. Exit in any case.
*/
if (gsi < 0) {
+ u32 dev_gsi;
dev_warn(&dev->dev, "PCI INT %c: no GSI", pin_name(pin));
/* Interrupt Line values above 0xF are forbidden */
- if (dev->irq > 0 && (dev->irq <= 0xF)) {
- printk(" - using IRQ %d\n", dev->irq);
- acpi_register_gsi(&dev->dev, dev->irq,
+ if (dev->irq > 0 && (dev->irq <= 0xF) &&
+ (acpi_isa_irq_to_gsi(dev->irq, &dev_gsi) == 0)) {
+ printk(" - using ISA IRQ %d\n", dev->irq);
+ acpi_register_gsi(&dev->dev, dev_gsi,
ACPI_LEVEL_SENSITIVE,
ACPI_ACTIVE_LOW);
return 0;
--
1.6.5.2.143.g8cc62

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