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From: Terry Reedy on 18 May 2010 13:11
On 5/18/2010 10:40 AM, J. Cliff Dyer wrote:
> Don't use regular expressions for that.
>
> s = '0x340x5A0x9B0xBA'
> return '0x' + ''.join(s.split('0x'))

or
>>> '0x'+s[2:].replace('0x','')
'0x345A9BBA'

Take your pick, you should learn and understand both.

> On Tue, 2010-05-18 at 06:48 -0700, Back9 wrote:
>> Hi,
>>
>> I have a string like this:
>> 0x340x5A0x9B0xBA
>> I want to extract 0x from the string but the first one.
>>
>> How I can use re for this case?
>>
>> The string size will vary.
>>
>> TIA
>>
>
>


From: Anthra Norell on 19 May 2010 03:26
Back9 wrote:
> Hi,
>
> I have a string like this:
> 0x340x5A0x9B0xBA
> I want to extract 0x from the string but the first one.
>
> How I can use re for this case?
>
> The string size will vary.
>
> TIA
>
>
Unless the use of a regular expression is a requirement I'd do it like this:

'0x%s' % s.split ('x', 1)[1].replace ('x', '')

Frederic

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