Surge / Ground / Lightning
in [Home Built PC]
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From: phil-news-nospam on 4 May 2008 12:57 In alt.tv.tech.hdtv John Doe <jdoe(a)usenetlove.invalid> wrote: | phil-news-nospam(a)ipal.net wrote: | |> In alt.tv.tech.hdtv bud-- <remove.budnews(a)isp.com> wrote: | |>| You have never provided a source that agrees with you on |>| disputed issues. |> |> Nor do I need to... | | You misspelled "cause I ain't got none". My sources predate the internet being the vast source of info it is today. They include discussions with EE professors, and observing the work of researchers. They also include analysis of events I've experienced, and also events described that others experienced. And some comes from an old ancient technology called a book (which I didn't get to keep because it came from a library). My interest in it was always about the physics of how it happens. -- |WARNING: Due to extreme spam, I no longer see any articles originating from | | Google Groups. If you want your postings to be seen by more readers | | you will need to find a different place to post on Usenet. | | Phil Howard KA9WGN (email for humans: first name in lower case at ipal.net) |
From: Timothy Daniels on 4 May 2008 13:01 "w_tom" wrote: > Will a high impedance stop or absorb what three miles of sky > could not? Of course not. Obviously not. And yet some just > know otherwise. Will that silly little one inch part inside a plug-in > protector stop what three miles of sky could not? Of course not. As always, "w_tom" ignores that the high voltages that short out "3 miles of sky" will short out the underground power lines which enter my building and buildings all over America. Anything able to leap "3 miles of sky" will leap the fraction of an inch between the power lines and the earthed metal conduit. What is left will be a much lower voltage spike that can be handled by the average "plug-in protector". *TimDaniels*
From: phil-news-nospam on 4 May 2008 13:02 In alt.tv.tech.hdtv Tony Hwang <dragon40(a)shaw.ca> wrote: | Michael A. Terrell wrote: |> Tony Hwang wrote: |> |>>Hi, |>>Is he a ham? What is his call sign? |>>Mine is VE6CGX. |> |> |> |> It's in his sig file: KA9WGN |> |> | Hmmm, | That is sign format of novice class. Which means my first ticket was novice. I upgraded a month after that. -- |WARNING: Due to extreme spam, I no longer see any articles originating from | | Google Groups. If you want your postings to be seen by more readers | | you will need to find a different place to post on Usenet. | | Phil Howard KA9WGN (email for humans: first name in lower case at ipal.net) |
From: phil-news-nospam on 4 May 2008 13:06 In alt.tv.tech.hdtv Tony Hwang <dragon40(a)shaw.ca> wrote: | phil-news-nospam(a)ipal.net wrote: |> In alt.tv.tech.hdtv Michael A. Terrell <mike.terrell(a)earthlink.net> wrote: |> |> | Bullshit. Like ALL charges, it simply seeks a complete circuit to |> | flow. You have absolutely no grasp of the basic concepts, yet you |> | continue to spout your ignorance and lies. |> |> Not true. |> |> When you close a switch between a power source and a pair of wires that go |> out yonder, the electrical energy does not "know" whether the circuit is |> complete or not. If it refused to flow, it would not be able to find out. |> It will flow, whether the circuit is complete or not. What happens after |> that depends on what is at the other end, which could be an open condition, |> a short circuit, or some kind of resistive or reactive load. |> |> You've claimed to have worked in broadcasting in an engineering role. So |> you should understand what happens at the end of an open transmission line. |> The electricity flows to get to the open end. Yet it is not a "complete |> circuit". |> | Hmmm, | You seem to be confused between current flow(energy) and | voltage(poential) Nothing flows in an open circuit. If not we have to | rewrite Ohm's law. Show your credential to make a stamement like that. | Shameful. Your knowledge of electricity shows to be a very basic level. You completely lack an understanding of how electricity does flow. You have no concept at all of transmission lines (and Michael A. Terrell seems to have forgotten his). Credentials have nothing to do with whether a statement is correct or not. Mine is correct but you don't have sufficient background to even understand it. -- |WARNING: Due to extreme spam, I no longer see any articles originating from | | Google Groups. If you want your postings to be seen by more readers | | you will need to find a different place to post on Usenet. | | Phil Howard KA9WGN (email for humans: first name in lower case at ipal.net) |
From: VWWall on 4 May 2008 13:12
Tony Hwang wrote: > phil-news-nospam(a)ipal.net wrote: >> In alt.tv.tech.hdtv Michael A. Terrell <mike.terrell(a)earthlink.net> >> wrote: >> >> | Bullshit. Like ALL charges, it simply seeks a complete circuit to >> | flow. You have absolutely no grasp of the basic concepts, yet you >> | continue to spout your ignorance and lies. >> >> Not true. >> >> When you close a switch between a power source and a pair of wires >> that go >> out yonder, the electrical energy does not "know" whether the circuit is >> complete or not. If it refused to flow, it would not be able to find >> out. >> It will flow, whether the circuit is complete or not. What happens after >> that depends on what is at the other end, which could be an open >> condition, >> a short circuit, or some kind of resistive or reactive load. >> >> You've claimed to have worked in broadcasting in an engineering role. So >> you should understand what happens at the end of an open transmission >> line. >> The electricity flows to get to the open end. Yet it is not a "complete >> circuit". >> > Hmmm, > You seem to be confused between current flow(energy) and > voltage(poential) Nothing flows in an open circuit. If not we have to > rewrite Ohm's law. Show your credential to make a stamement like that. > Shameful. Actually, a real current will flow until the line's capacitance is charged to the source voltage. When the source is removed, the energy involved will remain until it is leaked off through the inter-wire resistance. If the source is AC, no net energy will "flow", except that lost in the inter-wire resistance. If the line length is long enough at the frequency involved, reflections from the end of an incorrectly terminated transmission line will return to dissipate energy in the source resistance. -- Virg Wall, P.E. K6EVE |