(a==b) ? 'Yes' : 'No'
in [Python]
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From: Duncan Booth on 6 Apr 2010 12:54 Albert van der Horst <albert(a)spenarnc.xs4all.nl> wrote: > Old hands would have ... > stamp =( weight>=1000 and 120 or > weight>=500 and 100 or > weight>=250 and 80 or > weight>=100 and 60 or > 44 ) > > (Kind of a brain twister, I think, inferior to C, once the c-construct > is accepted as idiomatic.) I doubt many old hands would try to join multiple and/or operators that way. Most old hands would (IMHO) write the if statements out in full, though some might remember that Python comes 'batteries included': from bisect import bisect WEIGHTS = [100, 250, 500, 1000] STAMPS = [44, 60, 80, 100, 120] ... stamp = STAMPS[bisect(WEIGHTS,weight)] >>> map(lambda weight: STAMPS[bisect(WEIGHTS, weight)], [20, 100, 150, 999, 1000, 1100]) [44, 60, 60, 100, 120, 120]
From: Steven D'Aprano on 7 Apr 2010 00:20 On Tue, 06 Apr 2010 16:54:18 +0000, Duncan Booth wrote: > Albert van der Horst <albert(a)spenarnc.xs4all.nl> wrote: > >> Old hands would have ... >> stamp =( weight>=1000 and 120 or >> weight>=500 and 100 or >> weight>=250 and 80 or >> weight>=100 and 60 or >> 44 ) >> >> (Kind of a brain twister, I think, inferior to C, once the c-construct >> is accepted as idiomatic.) > > I doubt many old hands would try to join multiple and/or operators that > way. Most old hands would (IMHO) write the if statements out in full, > though some might remember that Python comes 'batteries included': > > from bisect import bisect > WEIGHTS = [100, 250, 500, 1000] > STAMPS = [44, 60, 80, 100, 120] > > ... > stamp = STAMPS[bisect(WEIGHTS,weight)] Isn't that an awfully heavyweight and obfuscated solution for choosing between five options? Fifty-five options, absolutely, but five? -- Steven
From: Emile van Sebille on 7 Apr 2010 12:28 On 4/6/2010 9:20 PM Steven D'Aprano said... > On Tue, 06 Apr 2010 16:54:18 +0000, Duncan Booth wrote: >> Most old hands would (IMHO) write the if statements out in full, >> though some might remember that Python comes 'batteries included': >> >> from bisect import bisect >> WEIGHTS = [100, 250, 500, 1000] >> STAMPS = [44, 60, 80, 100, 120] >> >> ... >> stamp = STAMPS[bisect(WEIGHTS,weight)] > > > Isn't that an awfully heavyweight and obfuscated solution for choosing > between five options? Fifty-five options, absolutely, but five? > Would it be easier to digest as: from bisect import bisect as selectindex # WEIGHTLIMITS = [100, 250, 500, 1000] POSTAGEAMOUNTS = [44, 60, 80, 100, 120] postage = POSTAGEAMOUNTS[selectindex(WEIGHTLIMITS, weight)] --- I've used bisect this way for some time -- I think Tim may have pointed it out -- and it's been handy ever since. Emile
From: Aahz on 12 Apr 2010 00:35 In article <mailman.1330.1269981186.23598.python-list(a)python.org>, Steve Holden <steve(a)holdenweb.com> wrote: > >It exists because people nagged Guido mercilessly until, against his >better judgment, he capitulated. No, the ternary exists because he became convinced that it was the lesser evil compared with letting the abomination of A and B or C remain the "Pythonic" ternary and someone came up with a syntax that wasn't completely painful. -- Aahz (aahz(a)pythoncraft.com) <*> http://www.pythoncraft.com/ "It is easier to optimize correct code than to correct optimized code." --Bill Harlan
From: Steven D'Aprano on 12 Apr 2010 02:35
On Sun, 11 Apr 2010 21:35:49 -0700, Aahz wrote: > In article <mailman.1330.1269981186.23598.python-list(a)python.org>, Steve > Holden <steve(a)holdenweb.com> wrote: >> >>It exists because people nagged Guido mercilessly until, against his >>better judgment, he capitulated. > > No, the ternary exists because he became convinced that it was the > lesser evil compared with letting the abomination of > > A and B or C > > remain the "Pythonic" ternary and someone came up with a syntax that > wasn't completely painful. As I recall, Guido himself got bitten by a subtle bug in the A and B or C idiom for ternary operator. Namely, if B is a false value, you get C even if A is true. -- Steven |