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From: Ed Morton on 8 Oct 2009 14:41
sharma__r(a)hotmail.com wrote:
> On Oct 8, 12:28 am, Ed Morton <mortons...(a)gmail.com> wrote:
>> On Oct 7, 1:57 pm, sharma...(a)hotmail.com wrote:
>> <snip>
>>
>>> Thanks for pointing that out. Actually it just needs a minor change:
>>> sed -e '
>>> :top
>>> /pattern1/!d
>>> n
>>> /pattern2/b
>>> btop
>>> ' yourfile
>>> -- Rakesh- Hide quoted text -
>> Just curious, if you don't mind indulging me: how would you enhance
>> that script if your requirements changed slightly to, say, print the
>> line numbers before the lines, i.e. the equivalent of changing this:
>>
>> awk '/Ultra/ {print; found=1; next}
>> found && /fixed/ {print}
>> {found=0}' file
>>
>> to this:
>>
>> awk '/Ultra/ {print NR,$0; found=1; next}
>> found && /fixed/ {print NR,$0}
>> {found=0}' file
>>
>> or if you wanted to only print the second line if it was longer than
>> 10 characters:
>>
>> awk '/Ultra/ {print; found=1; next}
>> found && /fixed/ && (length>10) {print}
>> {found=0}' file
>>
>> or if you wanted to, at the end of running the script, print a count
>> of all the lines that matched each pattern:
>>
>> awk '/Ultra/ {print; found=1; count1++; next}
>> found && /fixed/ {print; count2++}
>> {found=0}
>> END{print count1+0, count2+0}' file
>>
>> Regards,
>>
>> Ed.
>
>
> You could try this on a bourne-shell based command line:
>
> ## to print the line numbers alongwith the lines
> sed -e '
> :a
> /RE1/!d
> =;n
> /RE2/!ba
> =
> ' yourfile
>
>
> ## to print the second line only if it's length were more than 10
> characters.
> sed -e '
> :a
> /RE1/!d
> n
> /RE2/!ba
> /.\{10\}/!d
> ' yourfile
>
>
> -- Rakesh

Thanks!

Ed.
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