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From: Glenn Jackman on 16 Apr 2008 15:42
At 2008-04-16 03:08PM, "PugetSoundSylvia(a)gmail.com" wrote:
> In a string, I need to replace all instances of 15 or 16 number
> characters with the 11 or 12 "x" characters, then the last 4 digits of
> the 15 or 16 number characters. The chunk of number characters may
> appear numerous times in the string.

You want s/(\d{11,12})(\d{4})/"x" x length($1) . $2/eg

Note the 'e' modifier


--
Glenn Jackman
"If there is anything the nonconformist hates worse than a conformist,
it's another nonconformist who doesn't conform to the prevailing
standard of nonconformity." -- Bill Vaughan
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