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From: Francisco Jerez on 30 Jul 2010 08:00
Kulikov Vasiliy <segooon(a)gmail.com> writes:

> set_current_state() is called only once before the first iteration.
> After return from schedule_timeout() current state is TASK_RUNNING. If
> we are going to wait again, set_current_state() must be called.
>
> Signed-off-by: Kulikov Vasiliy <segooon(a)gmail.com>
> ---
> drivers/gpu/drm/nouveau/nouveau_fence.c | 3 ++-
> 1 files changed, 2 insertions(+), 1 deletions(-)
>
Thanks, I've pushed this patch to the Nouveau kernel tree.

> diff --git a/drivers/gpu/drm/nouveau/nouveau_fence.c b/drivers/gpu/drm/nouveau/nouveau_fence.c
> index 813d853..b7777ae 100644
> --- a/drivers/gpu/drm/nouveau/nouveau_fence.c
> +++ b/drivers/gpu/drm/nouveau/nouveau_fence.c
> @@ -186,7 +186,6 @@ nouveau_fence_wait(void *sync_obj, void *sync_arg, bool lazy, bool intr)
> unsigned long timeout = jiffies + (3 * DRM_HZ);
> int ret = 0;
>
> - __set_current_state(intr ? TASK_INTERRUPTIBLE : TASK_UNINTERRUPTIBLE);
>
> while (1) {
> if (nouveau_fence_signalled(sync_obj, sync_arg))
> @@ -197,6 +196,8 @@ nouveau_fence_wait(void *sync_obj, void *sync_arg, bool lazy, bool intr)
> break;
> }
>
> + __set_current_state(intr ? TASK_INTERRUPTIBLE
> + : TASK_UNINTERRUPTIBLE);
> if (lazy)
> schedule_timeout(1);
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