From: Yinghai Lu on
On 03/22/2010 02:52 PM, Benjamin Herrenschmidt wrote:
> On Mon, 2010-03-22 at 22:20 +0100, Ingo Molnar wrote:
>> So no arguments from me at all about the code quality aspects - i just wanted
>> to highlight the huge amount of non-trivial work Yinghai has invested into
>> this already, with little external help, and that if possible it would be nice
>> to minimize the upsetting of related x86 code if possible. Please help him out
>> with more specific suggestions about how the two memory allocation spaces
>> could be unified best, to serve the needs of all these architectures - if you
>> have some spare time.
> Why not start by unifying the APIs to it, while keeping the
> implementation in the arch for now ? That would be a good first step and
> would give us a good idea of what kind of requirements all the archs
> have since to some extent those requirements need to be represented in
> this API.

current early_res has


and don't have alloc, because it is equal to find + reserve.
all the find related will subtract reserved area already.
and it use start/end (goal/limit) and it will honor goal.

extern void reserve_early(u64 start, u64 end, char *name);
extern void reserve_early_overlap_ok(u64 start, u64 end, char *name);
extern void free_early(u64 start, u64 end);
void free_early_partial(u64 start, u64 end);
extern void early_res_to_bootmem(u64 start, u64 end);

void reserve_early_without_check(u64 start, u64 end, char *name);
u64 find_early_area(u64 ei_start, u64 ei_last, u64 start, u64 end,
u64 size, u64 align);
u64 find_early_area_size(u64 ei_start, u64 ei_last, u64 start,
u64 *sizep, u64 align);
u64 find_fw_memmap_area(u64 start, u64 end, u64 size, u64 align);
u64 get_max_mapped(void);
int get_free_all_memory_range(struct range **rangep, int nodeid);

lmd has:
and it does have lmb_find, but that doesn't subtract reserved area.

also lmb_alloc doesn't take goal. and only have limit there.

To unsubscribe from this list: send the line "unsubscribe linux-kernel" in
the body of a message to majordomo(a)
More majordomo info at
Please read the FAQ at