how to find and omit a directory containing a file entirely
in [Shell]
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From: Jerry Fleming on 13 May 2010 20:58 Hi, I want to use find to list my files, but exclude those in a directory containing a certain file. In the latest version of tar, there is --exclude-tag-all <http://www.gnu.org/software/tar/manual/html_section/exclude.html> to do this. I was wondering how to achieve the same effect using find. [quote] '--exclude-tag-all=file' Omit directories containing file file entirely. [/quote] Thanks.
From: Thomas 'PointedEars' Lahn on 13 May 2010 22:21 Jerry Fleming wrote: > I want to use find to list my files, but exclude those in a directory > containing a certain file. In the latest version of tar, there is > --exclude-tag-all > <http://www.gnu.org/software/tar/manual/html_section/exclude.html> to do > this. I was wondering how to achieve the same effect using find. find $PATHS \ -path $(find $PATHS -type d -exec test -e "{}/$FILE" \; -print) \ -prune -o -print should work (tested on Debian) if there is only one directory below $PATHS containing a file with name $FILE. You can perhaps use sed(1) or awk(1) to generate several -path expressions if there is more than one directory. PointedEars
From: Jerry Fleming on 14 May 2010 00:30 On 2010-05-14 10:21, Thomas 'PointedEars' Lahn wrote: > Jerry Fleming wrote: > >> I want to use find to list my files, but exclude those in a directory >> containing a certain file. In the latest version of tar, there is >> --exclude-tag-all >> <http://www.gnu.org/software/tar/manual/html_section/exclude.html> to do >> this. I was wondering how to achieve the same effect using find. > > find $PATHS \ > -path $(find $PATHS -type d -exec test -e "{}/$FILE" \; -print) \ > -prune -o -print > > should work (tested on Debian) if there is only one directory below $PATHS > containing a file with name $FILE. You can perhaps use sed(1) or awk(1) to > generate several -path expressions if there is more than one directory. > > > PointedEars Thanks. That does the trick. But I was wondering if there is anything builtin to find that can do the same thing. It turns out both -name and -path test only the current file system entry been stat'ed. Is there anything in find to conditionally -prune a directory based on its content? Jerry
From: Stephane CHAZELAS on 14 May 2010 09:33 2010-05-14, 08:58(+08), Jerry Fleming: [...] > I want to use find to list my files, but exclude those in a directory > containing a certain file. [...] find . -type d -exec sh -c '[ -e "$1/file" ]' sh {} \; -prune -o ... -- Stéphane
From: Thomas 'PointedEars' Lahn on 14 May 2010 11:41
Stephane CHAZELAS wrote: > Jerry Fleming wrote: > [...] >> I want to use find to list my files, but exclude those in a directory >> containing a certain file. > [...] > > find . -type d -exec sh -c '[ -e "$1/file" ]' sh {} \; -prune -o ... Clever solution, but ISTM this can be simplified to find . -type d -exec sh -c '[ -e "$1/file" ]' : '{}' \; -prune -o ... then find . -type d -exec sh -c '[ -e "$0/file" ]' '{}' \; -prune -o ... and then find . -type d -exec test -e '{}/file' \; -prune -o ... You may also use find . -type d -exec [ -e '{}/file' ] \; -prune -o ... instead. PointedEars |