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From: Sue on 8 Feb 2005 17:42
I have a text file in the following format -- I need to read and parse
this file and extract values for minDoseBinIndex and minimumDose. Any
pointers on how to do this will be of much help. I spend hours trying
to do this and all I have is code below which for some reason does not
work, I am not able to capture the values that I need. Can someone
PLEASE help? Thank you SO very much!

----------sample data file-----------------
voxelVolume: 0.004395
binSize: 0.163389
structureSetUID:

doseVolumeUID:
œ(A¼t @ëÿ@>*A¼t @
normalizationPointDose= 0.000000;
normalizationPoint={ 0.000000 0.000000 0.000000 };
numOfdvhCurves= 16;
dvhCurveList={
structure name: motion envelope
associatedROIUID: 0
minDoseBinIndex= 61203;
minimumDose= 10000.000000;
precedence= 10;
isTarget= 0;
numOfBins= 1;
voxelCounts={ 0
}
}



----------code extract------------------------

FileReader rd = new FileReader(strFileName);
StreamTokenizer st = new
StreamTokenizer(rd);


// Prepare the tokenizer for
Java-style tokenizing rules
st.parseNumbers();
//st.wordChars('_', '_');

st.eolIsSignificant(true);

// If whitespace is not to be
discarded, make this call
st.ordinaryChars(0, ' ');

// These calls caused comments to be
discarded
st.slashSlashComments(true);
st.slashStarComments(true);

// Parse the file
int token = st.nextToken();

while (token !=
StreamTokenizer.TT_EOF) {
token = st.nextToken();
switch (token) {
case StreamTokenizer.TT_NUMBER:
// A number was found; the
value is in nval
double num = st.nval;
System.out.println("num=" +
num);
// break;
case StreamTokenizer.TT_WORD:
// A word was found; the
value is in sval
//if
(st.sval.equals("minDoseBinIndex")) {
String word = st.sval;
System.out.println("word="
+ word);
// }

break;
case '"':
// A double-quoted string
was found; sval contains the contents
String dquoteVal = st.sval;
//
System.out.println("dquoteVal" + dquoteVal);
break;
case '\'':
// A single-quoted string
was found; sval contains the contents
String squoteVal = st.sval;
//
System.out.println("squoteVal=" + squoteVal);
break;
case StreamTokenizer.TT_EOL:
// End of line character
found
break;
case StreamTokenizer.TT_EOF:
// End of file has been
reached
break;
default:
// A regular character was
found; the value is the token itself
char ch = (char)st.ttype;
System.out.println("ch" +
ch);
break;
}
}
rd.close();
} catch (IOException et) {
}

From: dar7yl on 8 Feb 2005 19:34

"Sue" <sea_099(a)hotmail.com> wrote in message
news:1107902545.183720.258940(a)g14g2000cwa.googlegroups.com...
>> I have a text file in the following format -- I need to read and parse
>> this file and extract values for minDoseBinIndex and minimumDose. Any
>> pointers on how to do this will be of much help. I spend hours trying
>> to do this and all I have is code below which for some reason does not
>> work, I am not able to capture the values that I need. Can someone
>> PLEASE help? Thank you SO very much!

What is the expected output of your program, and what are you actually
getting?
What is the program doing when it fails. ie, what input line is it reading?
Is this your complete program?

You might want to create a mini-language, concentrating first on the
simplest form of the data you want to extract
vis:
<data> ::= <property> | <value>

<property> ::= <label> ':' <number>|<string>
// for instance 'structure name: motion envelope'

<value> ::= <label> '=' <number>|<array> ';'
// for instance 'minimumDose= 10000.000000;'
or 'normalizationPoint={ 0.000000 0.000000 0.000000 };'

Then design your parser to extract the appropriate elements, and place
them somewhere to be dealt with after the parsing is completed,
either on a line-by-line basis, or the complete file.

I suspect that your next assignment is to parse the dvhCurveList
which would involve a wee bit of recursion. You should structure
your solution to anticipate this.

regards,
Dar7yl




From: gimme_this_gimme_that on 8 Feb 2005 20:25
You can get it in a few lines if you use a regular expression.

I'm used to using the jakarta oro package.

If you agree to use oro I'll write up a solution.

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