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From: Fatemeh on 5 Jul 2008 05:24 Dear all; I'm going to use rlft3.f (3D Fast Fourier transform subroutine in Numerical Recipes book ) I have constructed a 107*107*107 mesh for data. I should call rlft3(data,speg,nn1,nn2,nn3,isign). ----------------------------------------------------------------------------- SUBROUTINE rlft3(data,speq,nn1,nn2,nn3,isign) INTEGER isign,nn1,nn2,nn3 COMPLEX data(nn1/2,nn2,nn3),speq(nn2,nn3) ----------------------------------------------------------------------------- 1- I don't understand why for data is written nn1/2 ? I have a 107*107*107 mesh!!! 2- Is it true to put nn1=nn2=nn3=107 3- I don't know what should I put instead of speq ? I'm anxiously looking forward your reply and guidlines. With my best regards, Fatemeh
From: dominiq on 5 Jul 2008 05:41 On 5 juil, 11:24, Fatemeh <fateme.mirj...(a)gmail.com> wrote: > Dear all; > > I'm going to use rlft3.f (3D Fast Fourier transform subroutine in > Numerical Recipes book ) > I have constructed a 107*107*107 mesh for data. > I should call rlft3(data,speg,nn1,nn2,nn3,isign). > --------------------------------------------------------------------------- -- > SUBROUTINE rlft3(data,speq,nn1,nn2,nn3,isign) > INTEGER isign,nn1,nn2,nn3 > COMPLEX data(nn1/2,nn2,nn3),speq(nn2,nn3) > --------------------------------------------------------------------------- -- > 1- I don't understand why for data is written nn1/2 ? I have a > 107*107*107 mesh!!! > 2- Is it true to put nn1=nn2=nn3=107 > 3- I don't know what should I put instead of speq ? > > I'm anxiously looking forward your reply and guidlines. > With my best regards, > Fatemeh The basic FFT requires sizes that are powers of 2. Some packages extend that to powers of small primes (typically 3 and 5), but I don't think this is the case for Numerical Recipes. Nevertheless 107 is a prime and is unlikely to be accepted in any FFT package. As a general advice RTFM before using any package! Dominique
From: Fatemeh on 5 Jul 2008 06:36 On Jul 5, 1:41 pm, dominiq <domi...(a)lps.ens.fr> wrote: > On 5 juil, 11:24, Fatemeh <fateme.mirj...(a)gmail.com> wrote: > > > > > Dear all; > > > I'm going to use rlft3.f (3D Fast Fourier transform subroutine in > > Numerical Recipes book ) > > I have constructed a 107*107*107 mesh for data. > > I should call rlft3(data,speg,nn1,nn2,nn3,isign). > > --------------------------------------------------------------------------- -- > > SUBROUTINE rlft3(data,speq,nn1,nn2,nn3,isign) > > INTEGER isign,nn1,nn2,nn3 > > COMPLEX data(nn1/2,nn2,nn3),speq(nn2,nn3) > > --------------------------------------------------------------------------- -- > > 1- I don't understand why for data is written nn1/2 ? I have a > > 107*107*107 mesh!!! > > 2- Is it true to put nn1=nn2=nn3=107 > > 3- I don't know what should I put instead of speq ? > > > I'm anxiously looking forward your reply and guidlines. > > With my best regards, > > Fatemeh > > The basic FFT requires sizes that are powers of 2. Some packages > extend that to powers of small primes (typically 3 and 5), but I don't > think this is the case for Numerical Recipes. Nevertheless 107 is a > prime and is unlikely to be accepted in any FFT package. > > As a general advice RTFM before using any package! > > Dominique Thanks for your guidelines. if I choose a size that is power of 2, about my another questions is there anyone that has some suggestion?
From: dominiq on 5 Jul 2008 08:00 On 5 juil, 12:36, Fatemeh <fateme.mirj...(a)gmail.com> wrote: > On Jul 5, 1:41 pm, dominiq <domi...(a)lps.ens.fr> wrote: > > > On 5 juil, 11:24, Fatemeh <fateme.mirj...(a)gmail.com> wrote: > > > > Dear all; > > > > I'm going to use rlft3.f (3D Fast Fourier transform subroutine in > > > Numerical Recipes book ) > > > I have constructed a 107*107*107 mesh for data. > > > I should call rlft3(data,speg,nn1,nn2,nn3,isign). > > > --------------------------------------------------------------------------- -- > > > SUBROUTINE rlft3(data,speq,nn1,nn2,nn3,isign) > > > INTEGER isign,nn1,nn2,nn3 > > > COMPLEX data(nn1/2,nn2,nn3),speq(nn2,nn3) > > > --------------------------------------------------------------------------- -- > > > 1- I don't understand why for data is written nn1/2 ? I have a > > > 107*107*107 mesh!!! > > > 2- Is it true to put nn1=nn2=nn3=107 > > > 3- I don't know what should I put instead of speq ? > > > > I'm anxiously looking forward your reply and guidlines. > > > With my best regards, > > > Fatemeh > > > The basic FFT requires sizes that are powers of 2. Some packages > > extend that to powers of small primes (typically 3 and 5), but I don't > > think this is the case for Numerical Recipes. Nevertheless 107 is a > > prime and is unlikely to be accepted in any FFT package. > > > As a general advice RTFM before using any package! > > > Dominique > > Thanks for your guidelines. > if I choose a size that is power of 2, about my another questions is > there anyone that has some suggestion? Since the multi-dimensional FFT takes the FFT along each dimension, each size has to be a power of 2. For the other questions read Numerical Recipes to know how to use the subroutine (aka RTFM!-). Dominique
From: James Van Buskirk on 5 Jul 2008 10:38 "dominiq" <dominiq(a)lps.ens.fr> wrote in message news:7061d478-b8c5-4a07-ab4f-9acb9d95d350(a)l64g2000hse.googlegroups.com... > The basic FFT requires sizes that are powers of 2. Some packages > extend that to powers of small primes (typically 3 and 5), but I don't > think this is the case for Numerical Recipes. Nevertheless 107 is a > prime and is unlikely to be accepted in any FFT package. 107 is kind of ugly because (107-1)/2 = 53 which I do in fact have an FFT for: http://home.comcast.net/~kmbtib/codelets.ZIP but 53 is rather ugly in itself. For some of these primes it gets more efficient to use the chirp-z method rather than Rader's method, but you can do an FFT of any order if you really have to. -- write(*,*) transfer((/17.392111325966148d0,6.5794487871554595D-85, & 6.0134700243160014d-154/),(/'x'/)); end
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