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From: Chris on 25 Jan 2006 18:34
My script takes user input and compare it with some values. It works
fine when it compares against 0.00 or 10 or 100. But if the user input
is something like "-0.009" it gives error - "integer expression
expected in line 7 and line 9" where it ought to print the number like
-

your number is -0.009.

Here's the code -

Code:

if [ "$num" = 0.00 ] || [ "$num" -le 10 ]; then # this is line 7
echo "your number is $num"
elif [ "$num" -ge "100" ]; then # this is line 9
echo "your number is greater than 100"
else
echo "your number is $num"

From: Wil Cooley on 25 Jan 2006 18:46
On Wed, 25 Jan 2006 15:34:24 -0800, Chris wrote:

> My script takes user input and compare it with some values. It works fine
> when it compares against 0.00 or 10 or 100. But if the user input is
> something like "-0.009" it gives error - "integer expression expected in
> line 7 and line 9" where it ought to print the number like -
>
> your number is -0.009.

The answer is so close you probably cannot see it:
"integer expression expected"

Is -0.009 an integer?

Wil

From: Chris F.A. Johnson on 25 Jan 2006 18:57
On 2006-01-25, Chris wrote:
> My script takes user input and compare it with some values. It works
> fine when it compares against 0.00 or 10 or 100. But if the user input
> is something like "-0.009" it gives error - "integer expression
> expected in line 7 and line 9" where it ought to print the number like
> -
>
> your number is -0.009.
>
> Here's the code -
>
> Code:
>
> if [ "$num" = 0.00 ] || [ "$num" -le 10 ]; then # this is line 7
> echo "your number is $num"
> elif [ "$num" -ge "100" ]; then # this is line 9
> echo "your number is greater than 100"
> else
> echo "your number is $num"

Read the error message. It tells you that an integer expression is
expected, not a decimal fraction. Bash does not use decimal
fractions, only integers.

--
Chris F.A. Johnson, author | <http://cfaj.freeshell.org>
Shell Scripting Recipes: | My code in this post, if any,
A Problem-Solution Approach | is released under the
2005, Apress | GNU General Public Licence
From: Stephane Chazelas on 26 Jan 2006 03:20
On 25 Jan 2006 15:34:24 -0800, Chris wrote:
> My script takes user input and compare it with some values. It works
> fine when it compares against 0.00 or 10 or 100. But if the user input
> is something like "-0.009" it gives error - "integer expression
> expected in line 7 and line 9" where it ought to print the number like
> -
>
> your number is -0.009.
>
> Here's the code -
>
> Code:
>
> if [ "$num" = 0.00 ] || [ "$num" -le 10 ]; then # this is line 7
> echo "your number is $num"
> elif [ "$num" -ge "100" ]; then # this is line 9
> echo "your number is greater than 100"
> else
> echo "your number is $num"

Only zsh and ksh93 support floating point arithmetics. Note that
[ ... = ... ] is string comparison (0 is different from 0.00).

To do floating point arithmetics portably, use awk.

--
Stephane
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