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This is an excerpt from the latest version perlfaq4.pod, which
comes with the standard Perl distribution. These postings aim to
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perlfaq is at http://faq.perl.org .

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4.23: How do I find matching/nesting anything?

This isn't something that can be done in one regular expression, no
matter how complicated. To find something between two single characters,
a pattern like "/x([^x]*)x/" will get the intervening bits in $1. For
multiple ones, then something more like "/alpha(.*?)omega/" would be
needed. But none of these deals with nested patterns. For balanced
expressions using "(", "{", "[" or "<" as delimiters, use the CPAN
module Regexp::Common, or see "(??{ code })" in perlre. For other cases,
you'll have to write a parser.

If you are serious about writing a parser, there are a number of modules
or oddities that will make your life a lot easier. There are the CPAN
modules "Parse::RecDescent", "Parse::Yapp", and "Text::Balanced"; and
the "byacc" program. Starting from perl 5.8 the "Text::Balanced" is part
of the standard distribution.

One simple destructive, inside-out approach that you might try is to
pull out the smallest nesting parts one at a time:

while (s/BEGIN((?:(?!BEGIN)(?!END).)*)END//gs) {
# do something with $1
}

A more complicated and sneaky approach is to make Perl's regular
expression engine do it for you. This is courtesy Dean Inada, and rather
has the nature of an Obfuscated Perl Contest entry, but it really does
work:

# $_ contains the string to parse
# BEGIN and END are the opening and closing markers for the
# nested text.

@( = ('(','');
@) = (')','');
($re=$_)=~s/((BEGIN)|(END)|.)/$)[!$3]\Q$1\E$([!$2]/gs;
@$ = (eval{/$re/},$@!~/unmatched/i);
print join("\n",@$[0..$#$]) if( $$[-1] );



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