From: PerlFAQ Server on 28 Apr 2010 00:00 This is an excerpt from the latest version perlfaq4.pod, which comes with the standard Perl distribution. These postings aim to reduce the number of repeated questions as well as allow the community to review and update the answers. The latest version of the complete perlfaq is at http://faq.perl.org . -------------------------------------------------------------------- 4.51: How do I permute N elements of a list? Use the "List::Permutor" module on CPAN. If the list is actually an array, try the "Algorithm::Permute" module (also on CPAN). It's written in XS code and is very efficient: use Algorithm::Permute; my @array = 'a'..'d'; my \$p_iterator = Algorithm::Permute->new ( \@array ); while (my @perm = \$p_iterator->next) { print "next permutation: (@perm)\n"; } For even faster execution, you could do: use Algorithm::Permute; my @array = 'a'..'d'; Algorithm::Permute::permute { print "next permutation: (@array)\n"; } @array; Here's a little program that generates all permutations of all the words on each line of input. The algorithm embodied in the "permute()" function is discussed in Volume 4 (still unpublished) of Knuth's *The Art of Computer Programming* and will work on any list: #!/usr/bin/perl -n # Fischer-Krause ordered permutation generator sub permute (&@) { my \$code = shift; my @idx = 0..\$#_; while ( \$code->(@_[@idx]) ) { my \$p = \$#idx; --\$p while \$idx[\$p-1] > \$idx[\$p]; my \$q = \$p or return; push @idx, reverse splice @idx, \$p; ++\$q while \$idx[\$p-1] > \$idx[\$q]; @idx[\$p-1,\$q]=@idx[\$q,\$p-1]; } } permute { print "@_\n" } split; The "Algorithm::Loops" module also provides the "NextPermute" and "NextPermuteNum" functions which efficiently find all unique permutations of an array, even if it contains duplicate values, modifying it in-place: if its elements are in reverse-sorted order then the array is reversed, making it sorted, and it returns false; otherwise the next permutation is returned. "NextPermute" uses string order and "NextPermuteNum" numeric order, so you can enumerate all the permutations of 0..9 like this: use Algorithm::Loops qw(NextPermuteNum); my @list= 0..9; do { print "@list\n" } while NextPermuteNum @list; -------------------------------------------------------------------- The perlfaq-workers, a group of volunteers, maintain the perlfaq. They are not necessarily experts in every domain where Perl might show up, so please include as much information as possible and relevant in any corrections. The perlfaq-workers also don't have access to every operating system or platform, so please include relevant details for corrections to examples that do not work on particular platforms. Working code is greatly appreciated. If you'd like to help maintain the perlfaq, see the details in perlfaq.pod.  |  Pages: 1 Prev: use constant behaviorNext: FAQ 5.25 How do I randomly update a binary file?