Opening file by partial name in same folder as master file
in [Programming]
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From: shiloh13 on 29 Mar 2010 00:42 Please Help!! I have a master file called "All Reports.xls" that opens up various Reports files(Ex: ABC_G016_GPUS.xls, BCD_G027_GPUS.xls, JKL_G034_GPUS.xls). The Report files are in the same network folder as the master file and are updated frequently. The Report files also have names that constantly change when they are updated. The only part of the filename that does not change begins with "G" followed by 3 numbers. By reading previous posts, I was able to figure out how to open the "G016" Report file with the code below. Workbooks.Open ActiveWorkbook.Path & "ABC_G016_GPUS.xls" How do I open the file by only the "G016" part of the filename? I tried the code below, but it did not work: Workbooks.Open ActiveWorkbook.Path & "*" & G016 & "*.xls" I appreciate your help!!
From: Gary Keramidas on 29 Mar 2010 00:56 maybe something like this: Sub test() Dim FileToOpen As String FileToOpen = Dir(ActiveWorkbook.Path & "*" & "G016" & "*.xls") If FileToOpen <> "" Then Workbooks.Open FileToOpen End If End Sub -- Gary Keramidas Excel 2003 "shiloh13" <u59050(a)uwe> wrote in message news:a5b747aa8da6d(a)uwe... > Please Help!! > > I have a master file called "All Reports.xls" that opens up various > Reports > files(Ex: ABC_G016_GPUS.xls, BCD_G027_GPUS.xls, JKL_G034_GPUS.xls). The > Report files are in the same network folder as the master file and are > updated frequently. The Report files also have names that constantly > change > when they are updated. The only part of the filename that does not change > begins with "G" followed by 3 numbers. By reading previous posts, I was > able > to figure out how to open the "G016" Report file with the code below. > > Workbooks.Open ActiveWorkbook.Path & "ABC_G016_GPUS.xls" > > How do I open the file by only the "G016" part of the filename? I tried > the > code below, but it did not work: > > Workbooks.Open ActiveWorkbook.Path & "*" & G016 & "*.xls" > > I appreciate your help!! >
From: Rick Rothstein on 29 Mar 2010 01:17 > Workbooks.Open FileToOpen The above line from your code should be this... Workbooks.Open ActiveWorkbook.Path & FileToOpen Since the Dir function returns only the file's name (without the path associated with it). -- Rick (MVP - Excel) "Gary Keramidas" <gkeramidas(a)MSN.com> wrote in message news:O$NCdzvzKHA.1236(a)TK2MSFTNGP06.phx.gbl... > maybe something like this: > > Sub test() > Dim FileToOpen As String > > FileToOpen = Dir(ActiveWorkbook.Path & "*" & "G016" & "*.xls") > If FileToOpen <> "" Then > Workbooks.Open FileToOpen > End If > > End Sub > > > -- > > > Gary Keramidas > Excel 2003 > > > "shiloh13" <u59050(a)uwe> wrote in message news:a5b747aa8da6d(a)uwe... >> Please Help!! >> >> I have a master file called "All Reports.xls" that opens up various >> Reports >> files(Ex: ABC_G016_GPUS.xls, BCD_G027_GPUS.xls, JKL_G034_GPUS.xls). The >> Report files are in the same network folder as the master file and are >> updated frequently. The Report files also have names that constantly >> change >> when they are updated. The only part of the filename that does not >> change >> begins with "G" followed by 3 numbers. By reading previous posts, I was >> able >> to figure out how to open the "G016" Report file with the code below. >> >> Workbooks.Open ActiveWorkbook.Path & "ABC_G016_GPUS.xls" >> >> How do I open the file by only the "G016" part of the filename? I tried >> the >> code below, but it did not work: >> >> Workbooks.Open ActiveWorkbook.Path & "*" & G016 & "*.xls" >> >> I appreciate your help!! >> >
From: Gary Keramidas on 29 Mar 2010 01:38 thanks -- Gary Keramidas Excel 2003 "Rick Rothstein" <rick.newsNO.SPAM(a)NO.SPAMverizon.net> wrote in message news:OBXzy8vzKHA.6112(a)TK2MSFTNGP05.phx.gbl... >> Workbooks.Open FileToOpen > > The above line from your code should be this... > > Workbooks.Open ActiveWorkbook.Path & FileToOpen > > Since the Dir function returns only the file's name (without the path > associated with it). > > -- > Rick (MVP - Excel) > > > > "Gary Keramidas" <gkeramidas(a)MSN.com> wrote in message > news:O$NCdzvzKHA.1236(a)TK2MSFTNGP06.phx.gbl... >> maybe something like this: >> >> Sub test() >> Dim FileToOpen As String >> >> FileToOpen = Dir(ActiveWorkbook.Path & "*" & "G016" & "*.xls") >> If FileToOpen <> "" Then >> Workbooks.Open FileToOpen >> End If >> >> End Sub >> >> >> -- >> >> >> Gary Keramidas >> Excel 2003 >> >> >> "shiloh13" <u59050(a)uwe> wrote in message news:a5b747aa8da6d(a)uwe... >>> Please Help!! >>> >>> I have a master file called "All Reports.xls" that opens up various >>> Reports >>> files(Ex: ABC_G016_GPUS.xls, BCD_G027_GPUS.xls, JKL_G034_GPUS.xls). The >>> Report files are in the same network folder as the master file and are >>> updated frequently. The Report files also have names that constantly >>> change >>> when they are updated. The only part of the filename that does not >>> change >>> begins with "G" followed by 3 numbers. By reading previous posts, I was >>> able >>> to figure out how to open the "G016" Report file with the code below. >>> >>> Workbooks.Open ActiveWorkbook.Path & "ABC_G016_GPUS.xls" >>> >>> How do I open the file by only the "G016" part of the filename? I tried >>> the >>> code below, but it did not work: >>> >>> Workbooks.Open ActiveWorkbook.Path & "*" & G016 & "*.xls" >>> >>> I appreciate your help!! >>> >>
From: OssieMac on 29 Mar 2010 04:00
I think that the backslash should also be included in both lines. Seems to be OK without if the current default directory is also the activeworkbook directory but can one be sure of that. Sub test() Dim FileToOpen As String FileToOpen = Dir(ActiveWorkbook.Path & "\" & "*" & "G016" & "*.xls") If FileToOpen <> "" Then Workbooks.Open ActiveWorkbook.Path & "\" & FileToOpen End If End Sub -- Regards, OssieMac "Rick Rothstein" wrote: > > Workbooks.Open FileToOpen > > The above line from your code should be this... > > Workbooks.Open ActiveWorkbook.Path & FileToOpen > > Since the Dir function returns only the file's name (without the path > associated with it). > > -- > Rick (MVP - Excel) > > > > "Gary Keramidas" <gkeramidas(a)MSN.com> wrote in message > news:O$NCdzvzKHA.1236(a)TK2MSFTNGP06.phx.gbl... > > maybe something like this: > > > > Sub test() > > Dim FileToOpen As String > > > > FileToOpen = Dir(ActiveWorkbook.Path & "*" & "G016" & "*.xls") > > If FileToOpen <> "" Then > > Workbooks.Open FileToOpen > > End If > > > > End Sub > > > > > > -- > > > > > > Gary Keramidas > > Excel 2003 > > > > > > "shiloh13" <u59050(a)uwe> wrote in message news:a5b747aa8da6d(a)uwe... > >> Please Help!! > >> > >> I have a master file called "All Reports.xls" that opens up various > >> Reports > >> files(Ex: ABC_G016_GPUS.xls, BCD_G027_GPUS.xls, JKL_G034_GPUS.xls). The > >> Report files are in the same network folder as the master file and are > >> updated frequently. The Report files also have names that constantly > >> change > >> when they are updated. The only part of the filename that does not > >> change > >> begins with "G" followed by 3 numbers. By reading previous posts, I was > >> able > >> to figure out how to open the "G016" Report file with the code below. > >> > >> Workbooks.Open ActiveWorkbook.Path & "ABC_G016_GPUS.xls" > >> > >> How do I open the file by only the "G016" part of the filename? I tried > >> the > >> code below, but it did not work: > >> > >> Workbooks.Open ActiveWorkbook.Path & "*" & G016 & "*.xls" > >> > >> I appreciate your help!! > >> > > > . > |