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From: superpollo on 17 Jun 2010 08:24
John Kelly ha scritto:
> On Thu, 17 Jun 2010 11:34:18 +0200, Marc Muehlfeld
> <marc.muehlfeld(a)web.de> wrote:
>
>> Am 17.06.2010 11:19, schrieb Chris F.A. Johnson:
>>> eq===========================================================================================
>>> num=20
>>> printf "%.${num}s\n" "$eq"
>>>
>>> Or:
>>>
>>> printf "%s\n" "${eq:0:$num}" ## not portable
>>
>> But this both command require the definition of a looooong line of "=" and I
>> don't know if I need 5, 20, 100, 5000,...
>
> Sounds like you want a string repeat operator or function. I can't
> think of any such feature in bash. Perl may have something like that.

or python:

[~/superpollo]$ N=20
[~/superpollo]$ python -c 'print "="*'$N
====================
[~/superpollo]$
From: Ed Morton on 17 Jun 2010 08:41
On 6/17/2010 3:35 AM, Marc Muehlfeld wrote:
> Hello,
>
> how can I print n equal signs in a shell script, without using a for
> loop, like
>
> for i in `seq 1 20` ; do
> echo -n "="
> done

$ printf "%020s\n" | tr '0' '='
====================

$ n=10
$ printf "%0""$n""s\n" | tr '0' '='
==========

> Is there a better way and just with bash build-ins?

Don't know if printf or tr are bash built-ins. Don't know why you'd care though.

Ed.
From: Ed Morton on 17 Jun 2010 08:59
On 6/17/2010 7:41 AM, Ed Morton wrote:
> On 6/17/2010 3:35 AM, Marc Muehlfeld wrote:
>> Hello,
>>
>> how can I print n equal signs in a shell script, without using a for
>> loop, like
>>
>> for i in `seq 1 20` ; do
>> echo -n "="
>> done
>
> $ printf "%020s\n" | tr '0' '='
> ====================
>
> $ n=10
> $ printf "%0""$n""s\n" | tr '0' '='
> ==========
>
>> Is there a better way and just with bash build-ins?
>
> Don't know if printf or tr are bash built-ins. Don't know why you'd care
> though.

....nor do I know why I thought "0" was a better char for replacement than " ":

$ printf "%20s\n" | tr ' ' '='
====================

$ n=10
$ printf '%'"$n"'s\n' | tr ' ' '='
==========

Sigh....

Ed.
From: pk on 17 Jun 2010 09:03
Marc Muehlfeld wrote:

> Hello,
>
> how can I print n equal signs in a shell script, without using a for loop,
> like
>
> for i in `seq 1 20` ; do
> echo -n "="
> done
>
> Is there a better way and just with bash build-ins?

With bash and builtins:

printf -v string "%30s" " "
echo "${string// /=}"

From: John Kelly on 17 Jun 2010 09:53
On Thu, 17 Jun 2010 07:59:31 -0500, Ed Morton <mortonspam(a)gmail.com>
wrote:

>> $ printf "%020s\n" | tr '0' '='
>> ====================

>...nor do I know why I thought "0" was a better char for replacement than " ":
>
>$ printf "%20s\n" | tr ' ' '='
>====================

Both produce a string of blanks. In the first example, you would need a
%d format specifier to get leading zeros.


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