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From: vanderghast on 11 May 2010 14:03
If there is no duplicated couple (type, [all bo]), then a join could be
faster :

SELECT a.[host dn], LAST(a.[all bo]), LAST(a.type), COUNT(*) as rank
FROM table AS a INNER JOIN table AS b
ON a.type < b.type
OR (a.type = b.type AND a.[all bo] <= b[all bo])
GROUP BY a.[host dn]

(I also assume Host DN are unique, no dup), else, we have to modify the
GROUP BY clause).


If there are dup, and if you want the low mark for equality (ie. ranks are
1, 1, 1, 4, 5 ... if there are 3 possible records for the first place,
all three get rank 1, and the fourth record get rank of 4, while there is no
second, no third, in that case), then you can use something like:

SELECT a.[host dn], a.[all bo], a.type,
(SELECT COUNT(*)
FROM table AS b
WHERE a.type < b.type
OR (a.type = b.type AND a.[all bo] <= b[all bo])) as rank
FROM table AS a



Haven't tested (typo or otherwise).



Vanderghast, Access MVP


"CBender" <CBender(a)discussions.microsoft.com> wrote in message
news:BB5F7C0D-C144-4D49-B918-71008311B7D7(a)microsoft.com...
> Hopefully THIS time the chart will post correctly!!!
>
> [Rank] [Host DN] [All BO] [Type]
> 1 328,155.34 831 3
> 2 134,728.16 416 3
> 3 1,415,578.32 87 2
> 4 987,821.27 69 2
> 5 15,578.32 1,566 1
> 6 1,878.81 865 1
> 7 543.02 72
> 8 89.19 43
>
> --
> Chip
>
>
> "CBender" wrote:
>
>> I am trying to Rank a field based on multiple sort criteria. My query
>> sorts
>> correctly, but the Ranking assignments are not correct. Could someone
>> please
>> review my SQL query and let me know how to correct this problem?
>>
>> I need to sort Descending by [Type2] AS WELL AS Descending by [Ext B/O]
>>
>>
>>
>> I used the following to assign my [Type2] field data:
>>
>> Type2: IIf([All BO]>=100 And [Host DN]>=20000,3,(IIf([Host
>> DN]>=20000,2,(IIf([All BO]>=100,1)))))
>>
>>
>> I am currently using the following to create my Ranking:
>>
>> Rank: (SELECT Count([VT].[Ext BO]) FROM [tmp_tbl_Chart5a_1] AS VT WHERE
>> VT.[Ext BO] > tmp_tbl_Chart5a_1.[Ext BO])+1
>>
>>
>> I know the Ranking I used sorts ONLY on the [Ext BO] field but I am not a
>> coder and do not know how to modify the format of my query to get what I
>> need.
>>
>>
>> Can someone please help??
>>
>>
>> Thanks,
>> --
>> Chip

From: CBender on 13 May 2010 17:02
Thanks for the support.

I do have duplicate values in the Ext BO field and I do get rankings that
are replicated like 1, 1, 1, 1, then I will get 5, 6, etc...

Is there a way to get these rankings to show as 1, 1, 1, 2, 3, 4, 4, 5, etc. ?


My SQL codeing is below:

SELECT (SELECT Count([VT].[Ext BO]) FROM [tbl_Chart5_Report4] AS VT WHERE
VT.[Ext BO] > tbl_Chart5_Report4.[Ext BO])+1 AS Rank,
tbl_Chart5_Report4.[Part Number], tbl_Chart5_Report4.[Host DN],
tbl_Chart5_Report4.[Ext BO], tbl_Chart5_Report4.[All BO]
FROM tbl_Chart5_Report4
GROUP BY tbl_Chart5_Report4.[Part Number], tbl_Chart5_Report4.[Host DN],
tbl_Chart5_Report4.[Ext BO], tbl_Chart5_Report4.[All BO]
ORDER BY tbl_Chart5_Report4.[Ext BO] DESC , tbl_Chart5_Report4.[All BO] DESC;



Thanks for your help!!!

--
Chip


"vanderghast" wrote:

> If there is no duplicated couple (type, [all bo]), then a join could be
> faster :
>
> SELECT a.[host dn], LAST(a.[all bo]), LAST(a.type), COUNT(*) as rank
> FROM table AS a INNER JOIN table AS b
> ON a.type < b.type
> OR (a.type = b.type AND a.[all bo] <= b[all bo])
> GROUP BY a.[host dn]
>
> (I also assume Host DN are unique, no dup), else, we have to modify the
> GROUP BY clause).
>
>
> If there are dup, and if you want the low mark for equality (ie. ranks are
> 1, 1, 1, 4, 5 ... if there are 3 possible records for the first place,
> all three get rank 1, and the fourth record get rank of 4, while there is no
> second, no third, in that case), then you can use something like:
>
> SELECT a.[host dn], a.[all bo], a.type,
> (SELECT COUNT(*)
> FROM table AS b
> WHERE a.type < b.type
> OR (a.type = b.type AND a.[all bo] <= b[all bo])) as rank
> FROM table AS a
>
>
>
> Haven't tested (typo or otherwise).
>
>
>
> Vanderghast, Access MVP
>
>
> "CBender" <CBender(a)discussions.microsoft.com> wrote in message
> news:BB5F7C0D-C144-4D49-B918-71008311B7D7(a)microsoft.com...
> > Hopefully THIS time the chart will post correctly!!!
> >
> > [Rank] [Host DN] [All BO] [Type]
> > 1 328,155.34 831 3
> > 2 134,728.16 416 3
> > 3 1,415,578.32 87 2
> > 4 987,821.27 69 2
> > 5 15,578.32 1,566 1
> > 6 1,878.81 865 1
> > 7 543.02 72
> > 8 89.19 43
> >
> > --
> > Chip
> >
> >
> > "CBender" wrote:
> >
> >> I am trying to Rank a field based on multiple sort criteria. My query
> >> sorts
> >> correctly, but the Ranking assignments are not correct. Could someone
> >> please
> >> review my SQL query and let me know how to correct this problem?
> >>
> >> I need to sort Descending by [Type2] AS WELL AS Descending by [Ext B/O]
> >>
> >>
> >>
> >> I used the following to assign my [Type2] field data:
> >>
> >> Type2: IIf([All BO]>=100 And [Host DN]>=20000,3,(IIf([Host
> >> DN]>=20000,2,(IIf([All BO]>=100,1)))))
> >>
> >>
> >> I am currently using the following to create my Ranking:
> >>
> >> Rank: (SELECT Count([VT].[Ext BO]) FROM [tmp_tbl_Chart5a_1] AS VT WHERE
> >> VT.[Ext BO] > tmp_tbl_Chart5a_1.[Ext BO])+1
> >>
> >>
> >> I know the Ranking I used sorts ONLY on the [Ext BO] field but I am not a
> >> coder and do not know how to modify the format of my query to get what I
> >> need.
> >>
> >>
> >> Can someone please help??
> >>
> >>
> >> Thanks,
> >> --
> >> Chip
>
From: vanderghast on 13 May 2010 17:13
There is a way, indeed, to get the dense rank, but again, the easiest one is
to use a sequence of query (which are called automatically, so there is no
visible complexity added at the user level).

A first query will be to remove the dups: call that query QNoDup, for
example.
Next, rank QNoDup records. Since there is no dup, you will get 1, 2, 3, 4,
5, ... for ranks. That makes QRank.
Finally, join the original data with the second query, getting the rank from
that second query, QRank. The dups are re-introduced, but the ranks have
already been computed, correctly, to produce the dense rank, so it is a job
done.



Vanderghast, Access MVP



"CBender" <CBender(a)discussions.microsoft.com> wrote in message
news:E5439602-6EE4-4574-9A3B-24BB4C32530D(a)microsoft.com...
> Thanks for the support.
>
> I do have duplicate values in the Ext BO field and I do get rankings that
> are replicated like 1, 1, 1, 1, then I will get 5, 6, etc...
>
> Is there a way to get these rankings to show as 1, 1, 1, 2, 3, 4, 4, 5,
> etc. ?
>
>
> My SQL codeing is below:
>
> SELECT (SELECT Count([VT].[Ext BO]) FROM [tbl_Chart5_Report4] AS VT
> WHERE
> VT.[Ext BO] > tbl_Chart5_Report4.[Ext BO])+1 AS Rank,
> tbl_Chart5_Report4.[Part Number], tbl_Chart5_Report4.[Host DN],
> tbl_Chart5_Report4.[Ext BO], tbl_Chart5_Report4.[All BO]
> FROM tbl_Chart5_Report4
> GROUP BY tbl_Chart5_Report4.[Part Number], tbl_Chart5_Report4.[Host DN],
> tbl_Chart5_Report4.[Ext BO], tbl_Chart5_Report4.[All BO]
> ORDER BY tbl_Chart5_Report4.[Ext BO] DESC , tbl_Chart5_Report4.[All BO]
> DESC;
>
>
>
> Thanks for your help!!!
>
> --
> Chip
>
>
> "vanderghast" wrote:
>
>> If there is no duplicated couple (type, [all bo]), then a join could be
>> faster :
>>
>> SELECT a.[host dn], LAST(a.[all bo]), LAST(a.type), COUNT(*) as rank
>> FROM table AS a INNER JOIN table AS b
>> ON a.type < b.type
>> OR (a.type = b.type AND a.[all bo] <= b[all bo])
>> GROUP BY a.[host dn]
>>
>> (I also assume Host DN are unique, no dup), else, we have to modify the
>> GROUP BY clause).
>>
>>
>> If there are dup, and if you want the low mark for equality (ie. ranks
>> are
>> 1, 1, 1, 4, 5 ... if there are 3 possible records for the first place,
>> all three get rank 1, and the fourth record get rank of 4, while there is
>> no
>> second, no third, in that case), then you can use something like:
>>
>> SELECT a.[host dn], a.[all bo], a.type,
>> (SELECT COUNT(*)
>> FROM table AS b
>> WHERE a.type < b.type
>> OR (a.type = b.type AND a.[all bo] <= b[all bo])) as rank
>> FROM table AS a
>>
>>
>>
>> Haven't tested (typo or otherwise).
>>
>>
>>
>> Vanderghast, Access MVP
>>
>>
>> "CBender" <CBender(a)discussions.microsoft.com> wrote in message
>> news:BB5F7C0D-C144-4D49-B918-71008311B7D7(a)microsoft.com...
>> > Hopefully THIS time the chart will post correctly!!!
>> >
>> > [Rank] [Host DN] [All BO] [Type]
>> > 1 328,155.34 831 3
>> > 2 134,728.16 416 3
>> > 3 1,415,578.32 87 2
>> > 4 987,821.27 69 2
>> > 5 15,578.32 1,566 1
>> > 6 1,878.81 865 1
>> > 7 543.02 72
>> > 8 89.19 43
>> >
>> > --
>> > Chip
>> >
>> >
>> > "CBender" wrote:
>> >
>> >> I am trying to Rank a field based on multiple sort criteria. My query
>> >> sorts
>> >> correctly, but the Ranking assignments are not correct. Could someone
>> >> please
>> >> review my SQL query and let me know how to correct this problem?
>> >>
>> >> I need to sort Descending by [Type2] AS WELL AS Descending by [Ext
>> >> B/O]
>> >>
>> >>
>> >>
>> >> I used the following to assign my [Type2] field data:
>> >>
>> >> Type2: IIf([All BO]>=100 And [Host DN]>=20000,3,(IIf([Host
>> >> DN]>=20000,2,(IIf([All BO]>=100,1)))))
>> >>
>> >>
>> >> I am currently using the following to create my Ranking:
>> >>
>> >> Rank: (SELECT Count([VT].[Ext BO]) FROM [tmp_tbl_Chart5a_1] AS VT
>> >> WHERE
>> >> VT.[Ext BO] > tmp_tbl_Chart5a_1.[Ext BO])+1
>> >>
>> >>
>> >> I know the Ranking I used sorts ONLY on the [Ext BO] field but I am
>> >> not a
>> >> coder and do not know how to modify the format of my query to get what
>> >> I
>> >> need.
>> >>
>> >>
>> >> Can someone please help??
>> >>
>> >>
>> >> Thanks,
>> >> --
>> >> Chip
>>

From: CBender on 20 May 2010 12:21
Vanderghast,

I appreciate ALL of your HELP and SUPPORT. Using a slightly modified
version of your suggested coding I greated my query (please see below). My
query correctly ranks my data from "1" to "whatever" based on the [Ext B/O]
field.

In my last meeting to present the data I was told an, "Oh yeah, by the way..."
Now they want me to include the [All B/O] field in the ranking as well. So,
the ranking should look at the unique record for [Part Number], the [Ext
B/O], AND the [All B/O] fields when assigning the ranking designations to the
data.

While [Part Number] indicates a UNIQUE record, there are occasionally
duplicate values for BOTH the [Ext B/O] and the [All B/O] field data for the
record.

If possible, I would LIKE to get rankings for 1, 2, 3, 4, 4, 4, 5, 6, 7, 7,
8, etc...

The records should be sorted:
Ascending by [Rank]
Descending by [Ext B/O]
Descending by [All B/O]
Ascending by [Part Number]

Here is a visual example of the ranking requested:

Rank Ext B/O All B/O Part Number
1 $18,498.10 92 4682840
2 $15,321.75 5 4563896
3 $13,836.60 12 3832851
4 $10,377.41 1285 1684846
4 $10,377.41 1285 3821173
5 $8,936.55 571 9274022
6 $5,215.58 63 4503211
7 $0.00 10 1
8 $0.00 9 2
9 $0.00 8 3

Here is the query I am currently using. Can you please let me know what
changes I need to make to get the results based on my new reporting
requirements?


SELECT
(SELECT Count([VT].[Ext B/O])

FROM [tbl_Chart5a_Report4] AS VT

WHERE VT.[Ext B/O] > tbl_Chart5a_Report4.[Ext B/O])+1 AS Rank,
tbl_Chart5a_Report4.[Part Number],
tbl_Chart5a_Report4.[Host DN],
tbl_Chart5a_Report4.[Ext B/O],
tbl_Chart5a_Report4.[All B/O]

FROM
tbl_Chart5a_Report4

GROUP BY
tbl_Chart5a_Report4.[Part Number],
tbl_Chart5a_Report4.[Host DN],
tbl_Chart5a_Report4.[Ext B/O],
tbl_Chart5a_Report4.[All B/O]

ORDER BY
tbl_Chart5a_Report4.[Ext B/O] DESC ,
tbl_Chart5a_Report4.[All B/O] DESC;



--
Chip


"vanderghast" wrote:

> There is a way, indeed, to get the dense rank, but again, the easiest one is
> to use a sequence of query (which are called automatically, so there is no
> visible complexity added at the user level).
>
> A first query will be to remove the dups: call that query QNoDup, for
> example.
> Next, rank QNoDup records. Since there is no dup, you will get 1, 2, 3, 4,
> 5, ... for ranks. That makes QRank.
> Finally, join the original data with the second query, getting the rank from
> that second query, QRank. The dups are re-introduced, but the ranks have
> already been computed, correctly, to produce the dense rank, so it is a job
> done.
>
>
>
> Vanderghast, Access MVP
>
>
>
> "CBender" <CBender(a)discussions.microsoft.com> wrote in message
> news:E5439602-6EE4-4574-9A3B-24BB4C32530D(a)microsoft.com...
> > Thanks for the support.
> >
> > I do have duplicate values in the Ext BO field and I do get rankings that
> > are replicated like 1, 1, 1, 1, then I will get 5, 6, etc...
> >
> > Is there a way to get these rankings to show as 1, 1, 1, 2, 3, 4, 4, 5,
> > etc. ?
> >
> >
> > My SQL codeing is below:
> >
> > SELECT (SELECT Count([VT].[Ext BO]) FROM [tbl_Chart5_Report4] AS VT
> > WHERE
> > VT.[Ext BO] > tbl_Chart5_Report4.[Ext BO])+1 AS Rank,
> > tbl_Chart5_Report4.[Part Number], tbl_Chart5_Report4.[Host DN],
> > tbl_Chart5_Report4.[Ext BO], tbl_Chart5_Report4.[All BO]
> > FROM tbl_Chart5_Report4
> > GROUP BY tbl_Chart5_Report4.[Part Number], tbl_Chart5_Report4.[Host DN],
> > tbl_Chart5_Report4.[Ext BO], tbl_Chart5_Report4.[All BO]
> > ORDER BY tbl_Chart5_Report4.[Ext BO] DESC , tbl_Chart5_Report4.[All BO]
> > DESC;
> >
> >
> >
> > Thanks for your help!!!
> >
> > --
> > Chip
> >
> >
> > "vanderghast" wrote:
> >
> >> If there is no duplicated couple (type, [all bo]), then a join could be
> >> faster :
> >>
> >> SELECT a.[host dn], LAST(a.[all bo]), LAST(a.type), COUNT(*) as rank
> >> FROM table AS a INNER JOIN table AS b
> >> ON a.type < b.type
> >> OR (a.type = b.type AND a.[all bo] <= b[all bo])
> >> GROUP BY a.[host dn]
> >>
> >> (I also assume Host DN are unique, no dup), else, we have to modify the
> >> GROUP BY clause).
> >>
> >>
> >> If there are dup, and if you want the low mark for equality (ie. ranks
> >> are
> >> 1, 1, 1, 4, 5 ... if there are 3 possible records for the first place,
> >> all three get rank 1, and the fourth record get rank of 4, while there is
> >> no
> >> second, no third, in that case), then you can use something like:
> >>
> >> SELECT a.[host dn], a.[all bo], a.type,
> >> (SELECT COUNT(*)
> >> FROM table AS b
> >> WHERE a.type < b.type
> >> OR (a.type = b.type AND a.[all bo] <= b[all bo])) as rank
> >> FROM table AS a
> >>
> >>
> >>
> >> Haven't tested (typo or otherwise).
> >>
> >>
> >>
> >> Vanderghast, Access MVP
> >>
> >>
> >> "CBender" <CBender(a)discussions.microsoft.com> wrote in message
> >> news:BB5F7C0D-C144-4D49-B918-71008311B7D7(a)microsoft.com...
> >> > Hopefully THIS time the chart will post correctly!!!
> >> >
> >> > [Rank] [Host DN] [All BO] [Type]
> >> > 1 328,155.34 831 3
> >> > 2 134,728.16 416 3
> >> > 3 1,415,578.32 87 2
> >> > 4 987,821.27 69 2
> >> > 5 15,578.32 1,566 1
> >> > 6 1,878.81 865 1
> >> > 7 543.02 72
> >> > 8 89.19 43
> >> >
> >> > --
> >> > Chip
> >> >
> >> >
> >> > "CBender" wrote:
> >> >
> >> >> I am trying to Rank a field based on multiple sort criteria. My query
> >> >> sorts
> >> >> correctly, but the Ranking assignments are not correct. Could someone
> >> >> please
> >> >> review my SQL query and let me know how to correct this problem?
> >> >>
> >> >> I need to sort Descending by [Type2] AS WELL AS Descending by [Ext
> >> >> B/O]
> >> >>
> >> >>
> >> >>
> >> >> I used the following to assign my [Type2] field data:
> >> >>
> >> >> Type2: IIf([All BO]>=100 And [Host DN]>=20000,3,(IIf([Host
> >> >> DN]>=20000,2,(IIf([All BO]>=100,1)))))
> >> >>
> >> >>
> >> >> I am currently using the following to create my Ranking:
> >> >>
> >> >> Rank: (SELECT Count([VT].[Ext BO]) FROM [tmp_tbl_Chart5a_1] AS VT
> >> >> WHERE
> >> >> VT.[Ext BO] > tmp_tbl_Chart5a_1.[Ext BO])+1
> >> >>
> >> >>
> >> >> I know the Ranking I used sorts ONLY on the [Ext BO] field but I am
> >> >> not a
> >> >> coder and do not know how to modify the format of my query to get what
> >> >> I
> >> >> need.
> >> >>
> >> >>
> >> >> Can someone please help??
> >> >>
> >> >>
> >> >> Thanks,
> >> >> --
> >> >> Chip
> >>
>
From: vanderghast on 20 May 2010 16:47
If you need to get a dense rank, your query where it is computed should
operate only on distinct data.


SELECT
(SELECT Count([VT].[Ext B/O])

FROM [tbl_Chart5a_Report4] AS VT

WHERE VT.[Ext B/O] > tbl_Chart5a_Report4.[Ext B/O])+1 AS Rank,
tbl_Chart5a_Report4.[Part Number],
tbl_Chart5a_Report4.[Host DN],
tbl_Chart5a_Report4.[Ext B/O],
tbl_Chart5a_Report4.[All B/O]

FROM
tbl_Chart5a_Report4

GROUP BY
tbl_Chart5a_Report4.[Part Number],
tbl_Chart5a_Report4.[Host DN],
tbl_Chart5a_Report4.[Ext B/O],
tbl_Chart5a_Report4.[All B/O]

ORDER BY
tbl_Chart5a_Report4.[Ext B/O] DESC ,
tbl_Chart5a_Report4.[All B/O] DESC;



you should try:


SELECT
(SELECT Count([VT].[Ext B/O])

FROM [queryWithDisttinctDataFromTbl_Chart5a_Report4] AS VT

WHERE VT.[Ext B/O] > tbl_Chart5a_Report4.[Ext B/O]
OR ( VT.[Ext B/O] = tbl_Chart5a_Report4.[Ext B/O]
AND ( VT.[All B/O] >= tbl_Chart5a_Report4.[All B/O]
) )
) +1 AS Rank,
tbl_Chart5a_Report4.[Part Number],
tbl_Chart5a_Report4.[Host DN],
tbl_Chart5a_Report4.[Ext B/O],
tbl_Chart5a_Report4.[All B/O]

FROM
tbl_Chart5a_Report4

GROUP BY
tbl_Chart5a_Report4.[Part Number],
tbl_Chart5a_Report4.[Host DN],
tbl_Chart5a_Report4.[Ext B/O],
tbl_Chart5a_Report4.[All B/O]

ORDER BY
tbl_Chart5a_Report4.[Ext B/O] DESC ,
tbl_Chart5a_Report4.[All B/O] DESC;



where queryWithDisttinctDataFromTbl_Chart5a_Report4 would be a saved query
returning the data without duplicated tuples (for the selected fields taken
together):

SELECT DISTINCT [Ext B/O], [All B/O]
FROM tbl_Chart5a_Report4



Vanderghast, Access MVP


"CBender" <CBender(a)discussions.microsoft.com> wrote in message
news:F0249B22-07DD-41AF-BD68-6DC457C66274(a)microsoft.com...
> Vanderghast,
>
> I appreciate ALL of your HELP and SUPPORT. Using a slightly modified
> version of your suggested coding I greated my query (please see below).
> My
> query correctly ranks my data from "1" to "whatever" based on the [Ext
> B/O]
> field.
>
> In my last meeting to present the data I was told an, "Oh yeah, by the
> way..."
> Now they want me to include the [All B/O] field in the ranking as well.
> So,
> the ranking should look at the unique record for [Part Number], the [Ext
> B/O], AND the [All B/O] fields when assigning the ranking designations to
> the
> data.
>
> While [Part Number] indicates a UNIQUE record, there are occasionally
> duplicate values for BOTH the [Ext B/O] and the [All B/O] field data for
> the
> record.
>
> If possible, I would LIKE to get rankings for 1, 2, 3, 4, 4, 4, 5, 6, 7,
> 7,
> 8, etc...
>
> The records should be sorted:
> Ascending by [Rank]
> Descending by [Ext B/O]
> Descending by [All B/O]
> Ascending by [Part Number]
>
> Here is a visual example of the ranking requested:
>
> Rank Ext B/O All B/O Part Number
> 1 $18,498.10 92 4682840
> 2 $15,321.75 5 4563896
> 3 $13,836.60 12 3832851
> 4 $10,377.41 1285 1684846
> 4 $10,377.41 1285 3821173
> 5 $8,936.55 571 9274022
> 6 $5,215.58 63 4503211
> 7 $0.00 10 1
> 8 $0.00 9 2
> 9 $0.00 8 3
>
> Here is the query I am currently using. Can you please let me know what
> changes I need to make to get the results based on my new reporting
> requirements?
>
>
> SELECT
> (SELECT Count([VT].[Ext B/O])
>
> FROM [tbl_Chart5a_Report4] AS VT
>
> WHERE VT.[Ext B/O] > tbl_Chart5a_Report4.[Ext B/O])+1 AS Rank,
> tbl_Chart5a_Report4.[Part Number],
> tbl_Chart5a_Report4.[Host DN],
> tbl_Chart5a_Report4.[Ext B/O],
> tbl_Chart5a_Report4.[All B/O]
>
> FROM
> tbl_Chart5a_Report4
>
> GROUP BY
> tbl_Chart5a_Report4.[Part Number],
> tbl_Chart5a_Report4.[Host DN],
> tbl_Chart5a_Report4.[Ext B/O],
> tbl_Chart5a_Report4.[All B/O]
>
> ORDER BY
> tbl_Chart5a_Report4.[Ext B/O] DESC ,
> tbl_Chart5a_Report4.[All B/O] DESC;
>
>
>
> --
> Chip
>
>
> "vanderghast" wrote:
>
>> There is a way, indeed, to get the dense rank, but again, the easiest one
>> is
>> to use a sequence of query (which are called automatically, so there is
>> no
>> visible complexity added at the user level).
>>
>> A first query will be to remove the dups: call that query QNoDup, for
>> example.
>> Next, rank QNoDup records. Since there is no dup, you will get 1, 2, 3,
>> 4,
>> 5, ... for ranks. That makes QRank.
>> Finally, join the original data with the second query, getting the rank
>> from
>> that second query, QRank. The dups are re-introduced, but the ranks have
>> already been computed, correctly, to produce the dense rank, so it is a
>> job
>> done.
>>
>>
>>
>> Vanderghast, Access MVP
>>
>>
>>
>> "CBender" <CBender(a)discussions.microsoft.com> wrote in message
>> news:E5439602-6EE4-4574-9A3B-24BB4C32530D(a)microsoft.com...
>> > Thanks for the support.
>> >
>> > I do have duplicate values in the Ext BO field and I do get rankings
>> > that
>> > are replicated like 1, 1, 1, 1, then I will get 5, 6, etc...
>> >
>> > Is there a way to get these rankings to show as 1, 1, 1, 2, 3, 4, 4, 5,
>> > etc. ?
>> >
>> >
>> > My SQL codeing is below:
>> >
>> > SELECT (SELECT Count([VT].[Ext BO]) FROM [tbl_Chart5_Report4] AS VT
>> > WHERE
>> > VT.[Ext BO] > tbl_Chart5_Report4.[Ext BO])+1 AS Rank,
>> > tbl_Chart5_Report4.[Part Number], tbl_Chart5_Report4.[Host DN],
>> > tbl_Chart5_Report4.[Ext BO], tbl_Chart5_Report4.[All BO]
>> > FROM tbl_Chart5_Report4
>> > GROUP BY tbl_Chart5_Report4.[Part Number], tbl_Chart5_Report4.[Host
>> > DN],
>> > tbl_Chart5_Report4.[Ext BO], tbl_Chart5_Report4.[All BO]
>> > ORDER BY tbl_Chart5_Report4.[Ext BO] DESC , tbl_Chart5_Report4.[All BO]
>> > DESC;
>> >
>> >
>> >
>> > Thanks for your help!!!
>> >
>> > --
>> > Chip
>> >
>> >
>> > "vanderghast" wrote:
>> >
>> >> If there is no duplicated couple (type, [all bo]), then a join could
>> >> be
>> >> faster :
>> >>
>> >> SELECT a.[host dn], LAST(a.[all bo]), LAST(a.type), COUNT(*) as rank
>> >> FROM table AS a INNER JOIN table AS b
>> >> ON a.type < b.type
>> >> OR (a.type = b.type AND a.[all bo] <= b[all bo])
>> >> GROUP BY a.[host dn]
>> >>
>> >> (I also assume Host DN are unique, no dup), else, we have to modify
>> >> the
>> >> GROUP BY clause).
>> >>
>> >>
>> >> If there are dup, and if you want the low mark for equality (ie. ranks
>> >> are
>> >> 1, 1, 1, 4, 5 ... if there are 3 possible records for the first
>> >> place,
>> >> all three get rank 1, and the fourth record get rank of 4, while there
>> >> is
>> >> no
>> >> second, no third, in that case), then you can use something like:
>> >>
>> >> SELECT a.[host dn], a.[all bo], a.type,
>> >> (SELECT COUNT(*)
>> >> FROM table AS b
>> >> WHERE a.type < b.type
>> >> OR (a.type = b.type AND a.[all bo] <= b[all bo])) as rank
>> >> FROM table AS a
>> >>
>> >>
>> >>
>> >> Haven't tested (typo or otherwise).
>> >>
>> >>
>> >>
>> >> Vanderghast, Access MVP
>> >>
>> >>
>> >> "CBender" <CBender(a)discussions.microsoft.com> wrote in message
>> >> news:BB5F7C0D-C144-4D49-B918-71008311B7D7(a)microsoft.com...
>> >> > Hopefully THIS time the chart will post correctly!!!
>> >> >
>> >> > [Rank] [Host DN] [All BO] [Type]
>> >> > 1 328,155.34 831 3
>> >> > 2 134,728.16 416 3
>> >> > 3 1,415,578.32 87 2
>> >> > 4 987,821.27 69 2
>> >> > 5 15,578.32 1,566 1
>> >> > 6 1,878.81 865 1
>> >> > 7 543.02 72
>> >> > 8 89.19 43
>> >> >
>> >> > --
>> >> > Chip
>> >> >
>> >> >
>> >> > "CBender" wrote:
>> >> >
>> >> >> I am trying to Rank a field based on multiple sort criteria. My
>> >> >> query
>> >> >> sorts
>> >> >> correctly, but the Ranking assignments are not correct. Could
>> >> >> someone
>> >> >> please
>> >> >> review my SQL query and let me know how to correct this problem?
>> >> >>
>> >> >> I need to sort Descending by [Type2] AS WELL AS Descending by [Ext
>> >> >> B/O]
>> >> >>
>> >> >>
>> >> >>
>> >> >> I used the following to assign my [Type2] field data:
>> >> >>
>> >> >> Type2: IIf([All BO]>=100 And [Host DN]>=20000,3,(IIf([Host
>> >> >> DN]>=20000,2,(IIf([All BO]>=100,1)))))
>> >> >>
>> >> >>
>> >> >> I am currently using the following to create my Ranking:
>> >> >>
>> >> >> Rank: (SELECT Count([VT].[Ext BO]) FROM [tmp_tbl_Chart5a_1] AS VT
>> >> >> WHERE
>> >> >> VT.[Ext BO] > tmp_tbl_Chart5a_1.[Ext BO])+1
>> >> >>
>> >> >>
>> >> >> I know the Ranking I used sorts ONLY on the [Ext BO] field but I am
>> >> >> not a
>> >> >> coder and do not know how to modify the format of my query to get
>> >> >> what
>> >> >> I
>> >> >> need.
>> >> >>
>> >> >>
>> >> >> Can someone please help??
>> >> >>
>> >> >>
>> >> >> Thanks,
>> >> >> --
>> >> >> Chip
>> >>
>>

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