Regular expression help
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From: Dr J R Stockton on 24 Mar 2010 10:30 In comp.lang.javascript message <66446dfb-e9cb-4d82-8146-377423e48aa8(a)k4 g2000prh.googlegroups.com>, Tue, 23 Mar 2010 16:32:24, RobG <rgqld(a)iinet.net.au> posted: > >Modifying the attribute value means that the result will be wrong. Is >there a regular expression that will only modify slashes outside >square brackets? > >An alternative is to fix the namespace when building the expression, >which is less elegant than conditionally modifying the expression in >the evaluator function. If you in fact only need to modify / where not somewhere preceded by [, you could probably split on [, RegExp-alter [0], and rejoin. expr = '/LandXML/Parcels/Parcel[@name="79a/SP199095"]' S = expr.split("[") S[0] = S[0].replace(/(\/+)/g,'$1xx:'); expr = S.join("[") gave '/xx:LandXML/xx:Parcels/xx:Parcel[@name="79a/SP199095"]'. Or you could use, which might be more flexible, expr = '/LandXML/Parcels/Parcel[@name="79a/SP199095"]' S = "" ; X = 0 for (J=0 ; J<expr.length ; J++) { C = expr.charAt(J) ; S += C if (C == "[") X++ ; else if (C == "]") X-- ; else if (C == "/" && X<=0) S += "xx:" } expr = S -- (c) John Stockton, nr London UK. ?@merlyn.demon.co.uk IE8 FF3 Op10 Sf4 Cr4 news:comp.lang.javascript FAQ <URL:http://www.jibbering.com/faq/index.html>. <URL:http://www.merlyn.demon.co.uk/js-index.htm> jscr maths, dates, sources. <URL:http://www.merlyn.demon.co.uk/> TP/BP/Delphi/jscr/&c, FAQ items, links.
From: Antony Scriven on 24 Mar 2010 13:48 On Mar 24, 3:51pm, ne...(a)no-log.org (denisb) wrote: > Antony Scriven <adscri...(a)gmail.com> wrote: > > [...] > > little typo ('+' missing) : > expr = expr.replace(/(?![^[]*\])\/+/g, '$&xx:'); > ....................................^ Ah yes, I missed that part of the Rob's specification, thanks. --Antony
From: RobG on 24 Mar 2010 18:38 On Mar 25, 1:09 am, Antony Scriven <adscri...(a)gmail.com> wrote: > On Mar 23, 11:32pm, RobG wrote: > > > [... ] I need to modify part of the expression to include > > a random namespace, e.g. change: > > > > /LandXML/Parcels/Parcel > > > > into something like: > > > > /xx:LandXML/xx:Parcels/xx:Parcel > > > > Sometimes the expression starts with // so I've been using the > > following regular expression: > > > > expr = expr.replace(/(\/+)/g,'$1xx:'); > > > > which works fine in most cases. However, sometimes the expression > > includes an attribute value that has slashes. In that case, I don't > > want to modify the attribute value's slash. e.g. at the moment, > > > > /LandXML/Parcels/Parcel[@name="79a/SP199095"] > > > > is converted to: > > > > /xx:LandXML/xx:Parcels/xx:Parcel[@name="79a/xx:SP199095"] > > > > Modifying the attribute value means that the result will be wrong. > Is > > there a regular expression that will only modify slashes outside > > square brackets? > > expr = expr.replace(/(?![^[]*\])\//g, '$&xx:'); > > Can your attribute value contain square brackets or escaped > quotation marks? --Antony It is for a general XPath expression evaluator, so I don't want to have any restrictions on attribute vaules other than those specified by XML. -- Rob
From: RobG on 24 Mar 2010 18:44 On Mar 25, 12:30 am, Dr J R Stockton <reply1...(a)merlyn.demon.co.uk> wrote: > In comp.lang.javascript message <66446dfb-e9cb-4d82-8146-377423e48aa8(a)k4 > g2000prh.googlegroups.com>, Tue, 23 Mar 2010 16:32:24, RobG > <rg...(a)iinet.net.au> posted: > > > > >Modifying the attribute value means that the result will be wrong. Is > >there a regular expression that will only modify slashes outside > >square brackets? > > >An alternative is to fix the namespace when building the expression, > >which is less elegant than conditionally modifying the expression in > >the evaluator function. > > If you in fact only need to modify / where not somewhere preceded by [, > you could probably split on [, RegExp-alter [0], and rejoin. > > expr = '/LandXML/Parcels/Parcel[@name="79a/SP199095"]' > S = expr.split("[") > S[0] = S[0].replace(/(\/+)/g,'$1xx:'); > expr = S.join("[") > > gave '/xx:LandXML/xx:Parcels/xx:Parcel[@name="79a/SP199095"]'. > > Or you could use, which might be more flexible, > > expr = '/LandXML/Parcels/Parcel[@name="79a/SP199095"]' > S = "" ; X = 0 > for (J=0 ; J<expr.length ; J++) { C = expr.charAt(J) ; S += C > if (C == "[") X++ ; > else if (C == "]") X-- ; > else if (C == "/" && X<=0) S += "xx:" } > expr = S I'd though of something along those lines, however I think I'll deal with it at the expression builder stage, then pass a variable to indicate whether a default namespace is being used or not. It doesn't matter for IE (as it doesn't know what namespaces are anyway), but Firefox is another matte. -- Rob
From: Antony Scriven on 24 Mar 2010 20:47
On Mar 24, 10:38 pm, RobG wrote: > On Mar 25, 1:09 am, Antony Scriven <adscri...(a)gmail.com> wrote: > > > On Mar 23, 11:32pm, RobG wrote: > > > > [...] > > > > > > expr = expr.replace(/(\/+)/g,'$1xx:'); > > > > > > [...] > > > > > > /LandXML/Parcels/Parcel[@name="79a/SP199095"] > > > > > > is converted to: > > > > > > /xx:LandXML/xx:Parcels/xx:Parcel[@name="79a/xx:SP199095"] > > > > > > Modifying the attribute value means that the result > > > will be wrong. Is there a regular expression that > > > will only modify slashes outside square brackets? > > > expr = expr.replace(/(?![^[]*\])\//g, '$&xx:'); > > > Can your attribute value contain square brackets or > > escaped quotation marks? --Antony > > It is for a general XPath expression evaluator, so > I don't want to have any restrictions on attribute vaules > other than those specified by XML. Now you're moving the goalposts. I've no idea what you're really trying to accomplish, but it now sounds that you might be better off writing a proper parser rather than messing about with regexps. --Antony |