Regular expression help
in [JavaScript]
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From: Elegie on 25 Mar 2010 16:49 RobG wrote: Hello Rob, <snip> > However, sometimes the expression > includes an attribute value that has slashes. In that case, I don't > want to modify the attribute value's slash. e.g. at the moment, > > /LandXML/Parcels/Parcel[@name="79a/SP199095"] > > is converted to: > > /xx:LandXML/xx:Parcels/xx:Parcel[@name="79a/xx:SP199095"] > > > Modifying the attribute value means that the result will be wrong. Is > there a regular expression that will only modify slashes outside > square brackets? The following should give you some path worth walking :) --- (s).replace( /\/([^[/]*(\[(\\.|[^\\\]]*)*\])?)/g, "/xx:$1" ) --- HTH, Elegie.
From: Antony Scriven on 25 Mar 2010 18:50
On Mar 25, 8:49 pm, Elegie wrote: > > [...] In that case, I don't want to modify the > > attribute value's slash. e.g. at the moment, > > > /LandXML/Parcels/Parcel[@name="79a/SP199095"] > > > is converted to: > > > /xx:LandXML/xx:Parcels/xx:Parcel[@name="79a/xx:SP199095"] > > > Modifying the attribute value means that the result > > will be wrong. Is there a regular expression that will > > only modify slashes outside square brackets? > > The following should give you some path worth walking :) > > --- > (s).replace( > /\/([^[/]*(\[(\\.|[^\\\]]*)*\])?)/g, > "/xx:$1" > ) Well, if you like brittle one-liners, try this. var s = '//LandXML/Parcels/Parcel[@name="]7]' + '9a/S\\"P19[9\\"]0/9[/5"]/Blah'; // Add xx: after slashes, only if they are not within "...". // Handles \" within "...". s.replace( /(\/+)(("([^"]*\\.)*[^"]*"|[^\/])+)/g, '$1xx:$2' ); There might be a neater regexp but I'm beginning to lose the will! And yes, this is now beginning to resemble line noise. --Antony |