Simple Thread exmple that I don't fully understand why it works as it does
in [CSharp]
|
Prev: Dictionary.Add() defeat already exists exception
Next: Simple Thread exmple that I don't fully understand why it worksas it does
From: Tony Johansson on 9 May 2010 13:27 Hi! Below is a really simple Thread example. If I run this example in debug mode and set a breakpoint in the SimpleWork why is not this row called immediately when this statement theThread.Start(); is executed. I have noticed that it is called first when I leave the main method I have tested several thing when this breakpoint in SimpleWork is hit 1. If I for example add a read in the main then as soon as this read has been executed this breakpoint in SimpleWork is hit 2. If I for example add a sleep on the main thread in main then this breakpoint in SimpleWork is hit as soon as this sleep is executing 3.If I for example add a WriteLine in the main then as soon as this WriteLine has been executed this breakpoint in SimpleWork is hit. This happen even if I have some other statement after this WriteLine. So my question is just what is it that cause the SimpleWork to be called. I mean in example 1 I have to leave the main method before the SimpleWork was called but in 2 I had to execute a readLine before the SimpleWork was called and in exemple 3 I had to execute a WriteLine before the SimpleWork was hit public static void Main() { ThreadStart operation = new ThreadStart(SimpleWork); Thread theThread = new Thread(operation); theThread.Start(); } private static void SimpleWork() { Console.WriteLine("Thread: {0}", Thread.CurrentThread.ManagedThreadId); } //Tony |