From: "Lawrance Shepstone" on
Hi Daniel,

Could you please tell us what version of PHP and OS you're using.

The following code fragment runs as expected on my PHP 5.3.2/Windows/XP/32bit:

<?php

header('Content-Type: text/plain');

class A
{
private function method_a( $argument )
{
echo('private method_a(\'' . $argument . '\') ...' . PHP_EOL );
}

public function __call( $method, $arguments )
{
if( method_exists( $this, $method ) && is_callable( array( $this, $method ) ) )
{
call_user_func_array( array( $this, $method ), $arguments );
}
else
{
echo('method \'' . $method . '\' either does not exist, or is not callable ...' . PHP_EOL );
}
}
}

$a = new A();

$a->method_a('argument');

$a->method_b('argument');

?>

Results in:

private method_a('argument') called ...
method 'method_b' either does not exist, or is not callable ...


Perhaps if you provided some code we could spot the problem.

I would guess there's something fishy in your __call() method.

Best of luck,
Lawrance

-----Original Message-----
From: Richard Quadling [mailto:rquadling(a)googlemail.com]
Sent: 12 May 2010 12:28 PM
To: Daniel Kolbo
Cc: PHP General
Subject: Re: [PHP] __call and recursion

On 9 May 2010 22:21, Daniel Kolbo <kolb0057(a)umn.edu> wrote:
> Hello,
>
> I've defined a __call() method inside a class. Within the __call()
> method (after testing that the method exists and is callable I am using:
>
> call_user_func_array(array($this,$method), $args);
>
> However, this seems to be an infinite loop (and is crashing my test
> apache server). How, could I still use the __call() method and avoid an
> infinite loop of calling?
>
> Thanks,
> dK

__call() is receiving $method.

Do you alter $method in any way?

If not, calling call_user_func(array($this, $method), $args) will
simply call the non-existent function.




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-----
Richard Quadling
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