From: monkeys paw on
I have the following acre meter which works for integers,
how do i convert this to float? I tried

return float ((208.0 * 208.0) * n)

>>> def s(n):
.... return lambda x: (208 * 208) * n
....
>>> f = s(1)
>>> f(1)
43264
>>> 208 * 208
43264
>>> f(.25)
43264
From: Patrick Maupin on
On Apr 6, 10:16 pm, monkeys paw <mon...(a)joemoney.net> wrote:
> I have the following acre meter which works for integers,
> how do i convert this to float? I tried
>
> return float ((208.0 * 208.0) * n)
>
>  >>> def s(n):
> ...     return lambda x: (208 * 208) * n
> ...
>  >>> f = s(1)
>  >>> f(1)
> 43264
>  >>> 208 * 208
> 43264
>  >>> f(.25)
> 43264

Not sure why you are returning a lambda (which is just a function that
does not have a name) from an outer function.

A function that does this multiplication would simply be:

def s(n):
return 208.0 * 208.0 * n

Regards,
Pat
From: Patrick Maupin on
On Apr 6, 11:04 pm, Patrick Maupin <pmau...(a)gmail.com> wrote:
> On Apr 6, 10:16 pm, monkeys paw <mon...(a)joemoney.net> wrote:
>
> > I have the following acre meter which works for integers,
> > how do i convert this to float? I tried
>
> > return float ((208.0 * 208.0) * n)
>
> >  >>> def s(n):
> > ...     return lambda x: (208 * 208) * n
> > ...
> >  >>> f = s(1)
> >  >>> f(1)
> > 43264
> >  >>> 208 * 208
> > 43264
> >  >>> f(.25)
> > 43264
>
> Not sure why you are returning a lambda (which is just a function that
> does not have a name) from an outer function.
>
> A function that does this multiplication would simply be:
>
> def s(n):
>     return 208.0 * 208.0 * n
>
> Regards,
> Pat


I realized I didn't show the use. A bit different than what you were
doing:

>>> def s(n):
.... return 208.0 * 208.0 * n
....
>>> s(1)
43264.0
>>> s(0.5)
21632.0
>>> s(3)
129792.0


I'm not sure exactly what you mean by "acre meter" though; this
returns the number of square feet in 'n' acres.

Regards,
Pat
From: Patrick Maupin on
On Apr 6, 11:10 pm, Patrick Maupin <pmau...(a)gmail.com> wrote:
> On Apr 6, 11:04 pm, Patrick Maupin <pmau...(a)gmail.com> wrote:
>
>
>
> > On Apr 6, 10:16 pm, monkeys paw <mon...(a)joemoney.net> wrote:
>
> > > I have the following acre meter which works for integers,
> > > how do i convert this to float? I tried
>
> > > return float ((208.0 * 208.0) * n)
>
> > >  >>> def s(n):
> > > ...     return lambda x: (208 * 208) * n
> > > ...
> > >  >>> f = s(1)
> > >  >>> f(1)
> > > 43264
> > >  >>> 208 * 208
> > > 43264
> > >  >>> f(.25)
> > > 43264
>
> > Not sure why you are returning a lambda (which is just a function that
> > does not have a name) from an outer function.
>
> > A function that does this multiplication would simply be:
>
> > def s(n):
> >     return 208.0 * 208.0 * n
>
> > Regards,
> > Pat
>
> I realized I didn't show the use.  A bit different than what you were
> doing:
>
> >>> def s(n):
>
> ...     return 208.0 * 208.0 * n
> ...>>> s(1)
> 43264.0
> >>> s(0.5)
> 21632.0
> >>> s(3)
>
> 129792.0
>
> I'm not sure exactly what you mean by "acre meter" though; this
> returns the number of square feet in 'n' acres.
>
> Regards,
> Pat

I should stop making a habit of responding to myself, BUT. This isn't
quite an acre in square feet. I just saw the 43xxx and assumed it
was, and then realized it couldn't be, because it wasn't divisible by
10. (I used to measure land with my grandfather with a 66 foot long
chain, and learned at an early age that an acre was 1 chain by 10
chains, or 66 * 66 * 10 = 43560 sqft.)
That's an exact number, and 208 is a poor approximation of its square
root.

Regards,
Pat
From: Peter Pearson on
On Tue, 06 Apr 2010 23:16:18 -0400, monkeys paw <monkey(a)joemoney.net> wrote:
> I have the following acre meter which works for integers,
> how do i convert this to float? I tried
>
> return float ((208.0 * 208.0) * n)
>
> >>> def s(n):
> ... return lambda x: (208 * 208) * n
> ...
> >>> f = s(1)
> >>> f(1)
> 43264
> >>> 208 * 208
> 43264
> >>> f(.25)
> 43264

The expression "lambda x: (208 * 208) * n" is independent of x.
Is that what you intended?


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