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From: demin on 30 Oct 2009 11:57
I found the simple kappa value different in proc freq:
proc freq; (by default order=internal)
proc freq order=data;
why? The simple kappa will be higher in order=internal than in
order=data;

order=DATA
orders values according to their order in the input data set.
order=INTERNAL
orders values by their unformatted values, which yields the same order
that the SORT procedure does. This order is operating-environment
dependent.

proc freq data=aaa;
tables q11ts6s1*q11ts6s1r2 q11ts6s2*q11ts6s2r2 / nocol norow agree;
run;

why this happen? related to the definition of simple kappa
coefficient? thanks.
From: John Uebersax on 30 Oct 2009 23:48
Would this option affect the match-up of levels of your two
variables? For example, suppose one has two formatted integer
variables:

X: 1 = 'Low', 2 = 'Med', 3 = 'High'
Y: 1 = '1Low', 2 = '2Med', 3 = '3High'

The numeric values of X and Y would match up correctly, but not the
formatted variables (because the alphanumeric ordering of X is 'Low',
'High', 'Med'.
This would affect the kappa value, which depends on which cells are on
the diagonal of the 2-way table.

Hope this helps.

Also maybe check some of the comments here:
http://www.john-uebersax.com/stat/saskappa.htm

John Uebersax
http://www.john-uebersax.com


On Oct 30, 8:57 am, demin <qdmi...(a)gmail.com> wrote:
> I found the simple kappa value different in proc freq:
> proc freq; (by default order=internal)
> proc freq order=data;
> why? The simple kappa will be higher in order=internal than in
> order=data;
>
> order=DATA
> orders values according to their order in the input data set.
> order=INTERNAL
> orders values by their unformatted values, which yields the same order
> that the SORT procedure does. This order is operating-environment
> dependent.
>
> proc freq data=aaa;
> tables q11ts6s1*q11ts6s1r2 q11ts6s2*q11ts6s2r2 / nocol norow agree;
> run;
>
> why this happen? related to the definition of simple kappa
> coefficient?  thanks.






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