From: PhilipOrr on
Many thanks again for your thoughts. Fred - yes, your model is correct I
think. That's what's happening.

The more you all explain this the more the scheme seems pointless! So
basically, unless I have some strong common-mode signals I want to reduce,
there is no use to the subtraction because it will only improve my SNR by a
factor of 1.414, because the random noise increases.

Maybe instead I should try something like driving the switch like a
modulator at fswitch << sample rate, and then use something like a lock-in
amp to get the signal power at fswitch, using the switch driving signal as
the lock-in reference. It would take more development but frankly now the
differential scheme seems pretty silly.

Philip
From: Jerry Avins on
On 7/23/2010 4:47 AM, PhilipOrr wrote:
> Many thanks again for your thoughts. Fred - yes, your model is correct I
> think. That's what's happening.
>
> The more you all explain this the more the scheme seems pointless! So
> basically, unless I have some strong common-mode signals I want to reduce,
> there is no use to the subtraction because it will only improve my SNR by a
> factor of 1.414, because the random noise increases.
>
> Maybe instead I should try something like driving the switch like a
> modulator at fswitch<< sample rate, and then use something like a lock-in
> amp to get the signal power at fswitch, using the switch driving signal as
> the lock-in reference. It would take more development but frankly now the
> differential scheme seems pretty silly.

Whatever scheme you finally hit on will have far better success if you
identify the major noise mechanism. It is nearly futile to try to
mitigate a problem you know little about.

Jerry
--
Engineering is the art of making what you want from things you can get.
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From: Michael Plante on
Jerry wrote:
>On 7/21/2010 8:12 PM, PhilipOrr wrote:
>> Hi everyone - this is my first post here. It's about time I joined a
DSP
>> forum.
>>
>> I need some advice related to a measurement system. The system samples
at 1
>> kHz but between every sample the input to the DAQ is switched between
two
>> inputs. The result is that the acquired signal, at 1 kHz, is two
>> interleaved signals at 500 Hz each.
>>
>
>...that precedes ADC. (You wrote DAC, but I don't think you meant
>that.) ...

Perhaps a nitpick, but he wrote DAQ, not DAC, and I've seen that in the
context of Labview/NI to mean "Data AcQuisition unit". I.e., a packaged
ADC. That term threw me off a bit too when I first heard it, because it is
pronounced like "DAC", but really means "ADC". Fun stuff...

From: PhilipOrr on
>Perhaps a nitpick, but he wrote DAQ, not DAC, and I've seen that in the
>context of Labview/NI to mean "Data AcQuisition unit". I.e., a packaged
>ADC. That term threw me off a bit too when I first heard it, because it
is
>pronounced like "DAC", but really means "ADC". Fun stuff...

Yep, sorry for the confusion. I wrote DAQ deliberately to mean
data-acquisition not DAC. Must be a LabVIEW term only.
From: Jerry Avins on
On 7/26/2010 12:45 AM, Michael Plante wrote:
> Jerry wrote:

>> ...that precedes ADC. (You wrote DAC, but I don't think you meant
>> that.) ...
>
> Perhaps a nitpick, but he wrote DAQ, not DAC, and I've seen that in the
> context of Labview/NI to mean "Data AcQuisition unit". I.e., a packaged
> ADC. That term threw me off a bit too when I first heard it, because it is
> pronounced like "DAC", but really means "ADC". Fun stuff...

Thanks for the heads-up. I apologize to P.O. for my poor reading.

Jerry
--
Engineering is the art of making what you want from things you can get.
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