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From: amelia jane on 17 May 2010 20:04
Hello folks,

I have the following pseudo code:

#define MY_DEF 10

void my_func(void)
{

int i, loopcount = 0, offset = 6;
for (i = 0; i< ((MY_DEF-offset)/2); i++)
{
loopcount++;
}

printf("loopcount=%d\n",loopcount);
}

The above code, instead of printing loopcount=2 prints loopcount=1;

If I make the following modification to the code:

void my_func(void)
{

int i, loopnumber = 0; loopcount = 0, offset = 6;

loopnumber = (MY_DEF-offset)/2;
for (i = 0; i< loopnumber; i++)
{
loopcount++;
}

printf("loopcount=%d\n",loopcount);
}

This code prints out loopcount=2.

I am a bit confused on why this is the case. Any thoughts on this are
welcome.
From: Patricia Shanahan on 17 May 2010 20:15
amelia jane wrote:
> Hello folks,
>
> I have the following pseudo code:

The term "pseudo code" suggests that what you posted is not *exactly*
what you ran. This type of problem depends on details, so it might be
better to select a programming language, and post a complete program in
that language that shows the effect you want to understand.

Patricia
From: Dann Corbit on 17 May 2010 20:57
In article <b1c7d97c-afba-4741-813e-7cd9819a6b31
@v12g2000prb.googlegroups.com>, ameliajane42(a)gmail.com says...
>
> Hello folks,
>
> I have the following pseudo code:
>
> #define MY_DEF 10
>
> void my_func(void)
> {
>
> int i, loopcount = 0, offset = 6;
> for (i = 0; i< ((MY_DEF-offset)/2); i++)
> {
> loopcount++;
> }
>
> printf("loopcount=%d\n",loopcount);
> }
>
> The above code, instead of printing loopcount=2 prints loopcount=1;
>
> If I make the following modification to the code:
>
> void my_func(void)
> {
>
> int i, loopnumber = 0; loopcount = 0, offset = 6;
>
> loopnumber = (MY_DEF-offset)/2;
> for (i = 0; i< loopnumber; i++)
> {
> loopcount++;
> }
>
> printf("loopcount=%d\n",loopcount);
> }
>
> This code prints out loopcount=2.
>
> I am a bit confused on why this is the case. Any thoughts on this are
> welcome.

#include <stdio.h>
#include <stdlib.h>

#define MY_DEF 10

void my_func0(void)
{

int i,
loopcount = 0,
offset = 6;
for (i = 0; i < ((MY_DEF - offset) / 2); i++) {
loopcount++;
}

printf("loopcount=%d\n", loopcount);
}


void my_func1(void)
{

int i,
loopnumber = 0;
int loopcount = 0, offset = 6;

loopnumber = (MY_DEF - offset) / 2;
for (i = 0; i < loopnumber; i++) {
loopcount++;
}

printf("loopcount=%d\n", loopcount);
}


int main(void)
{
my_func0();
my_func1();
return 0;
}

/* After removal of obvious syntax errors, I get this:
loopcount=2
loopcount=2
*/
From: pete on 17 May 2010 23:22
amelia jane wrote:
>
> Hello folks,
>
> I have the following pseudo code:
>
> #define MY_DEF 10

> void my_func(void)
> {
>
> int i, loopnumber = 0; loopcount = 0, offset = 6;
>
> loopnumber = (MY_DEF-offset)/2;
> for (i = 0; i< loopnumber; i++)
> {
> loopcount++;
> }
>
> printf("loopcount=%d\n",loopcount);
> }
>
> This code prints out loopcount=2.
>
> I am a bit confused on why this is the case. Any thoughts on this are
> welcome.

loopnumber is assigned a value of two.
The loop executes twice.
loopcount starts at zero and increments twice.

--
pete
From: amelia jane on 19 May 2010 01:51
On May 17, 8:22 pm, pete <pfil...(a)mindspring.com> wrote:
> amelia jane wrote:
>
> > Hello folks,
>
> > I have the following pseudo code:
>
> > #define MY_DEF 10
> > void my_func(void)
> > {
>
> > int i, loopnumber = 0; loopcount = 0, offset = 6;
>
> > loopnumber = (MY_DEF-offset)/2;
> > for (i = 0; i< loopnumber; i++)
> > {
> >     loopcount++;
> > }
>
> > printf("loopcount=%d\n",loopcount);
> > }
>
> > This code prints out loopcount=2.
>
> > I am a bit confused on why this is the case. Any thoughts on this are
> > welcome.
>
> loopnumber is assigned a value of two.
> The loop executes twice.
> loopcount starts at zero and increments twice.
>
> --
> pete

Thanks for the responses so far. For the benefit of everyone, here is
the original piece of code in C:

#define MY_DEF 10

void my_func(void)
{
int i;
int loopcount;
int offset = 6;
loopcount = 0;

for (i = 0; i< ((MY_DEF-offset)/2); i++)
{
loopcount++;
}

printf("loopcount=%d\n",loopcount);
}

main()
{
my_func();
}

I still don't get why loopcount equals 1;
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